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postnew [5]
3 years ago
15

Find the momentum of a 25 kg object going 4m/s to the right.

Physics
1 answer:
Ronch [10]3 years ago
7 0
X=mass × velocity
x=25×4
=100kgm/s
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The pupil of a cat's eye narrows to a slit width of 0.5 mm in daylight. What is the angular resolution of the cat's eye in dayli
Elenna [48]

Answer:

C. 10⁻³ rads

Explanation:

Here, we shall use Rayleigh's Criterion to find out the angular resolution of Cat's eye during day light. Rayleigh's Criterion is written as follows:

θ = λ/a

where,

θ = angular resolution of Cat's eye = ?

λ = wavelength = 500 nm = 5 x 10⁻⁷ m

a = slit width of eye = 0.5 mm = 5 x 10⁻⁴ m

Therefore,

θ = (5 x 10⁻⁷ m/5 x 10⁻⁴ m)

Therefore,

θ = 0.001

θ = Sin⁻¹(0.001)

θ = 0.001 rad = 1 x 10⁻³ rad

Hence, the correct answer is:

<u>C. 10⁻³ rads</u>

4 0
3 years ago
Fenómeno químico en virtud del cual se transforma un cuerpo o compuesto por la accion de un oxidante
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Chemical phenomenon by virtue of which a body or compound is transformed by the action of an oxidant
3 0
3 years ago
Which of these is an example of an experiment?
Vsevolod [243]
Add different quantities of water to three potted plants
7 0
3 years ago
Sometimes you can see a faint reflection in the surface of a shiny plate or cup.Why ?
bazaltina [42]

Answer:

The degree of reflection whether faint or bright you see on the surface of an object is an indication that light particles had hit the surface. Since light is a wave and as part of its characteristics can get reflected. However, the amount of light reflected by a surface is dependent on the smoothness of the surface which can be shiny or dull, it can also be dependent on the nature of the surface which can be glass, water, and so on. So, from the question, you can see a faint reflection on the surface of a shiny plate or cup because of the smoothness of the surface which reflects the lights that hit it from a particular direction at the same angle.

4 0
3 years ago
With what type of electromagnetic radiation would you observe:
Viefleur [7K]

Answer:

Green part of the visible spectrum.

X ray part of the electromagnetic spectrum.

Infrared part of the electromagnetic spectrum.

Explanation:

Wien's displacement law

\lambda_{max}=\frac{b}{T}

Where, b = Wien's displacement constant = 2.898×10⁻³ mK

T = Temperature in kelvin

\lambda_{max}=\frac{2.898\times 10^{-3}}{5800}\\\Rightarrow\lambda_{max}=0.499\times 10^{-6}=0.5\mu m=500\ nm

So, the wavelength would be of around the green part of the visible spectrum.

\lambda_{max}=\frac{2.898\times 10^{-3}}{1\times 10^6}\\\Rightarrow\lambda_{max}=2.898\times 10^{-9}=2.898\ nm

So, the wavelength would be of around the X ray part of the electromagnetic spectrum.

Human body temperature = 37°C = 37+273.15 = 310.15 K

\lambda_{max}=\frac{2.898\times 10^{-3}}{37+273.15}\\\Rightarrow\lambda_{max}=\frac{2.898\times 10^{-3}}{310.15}\\\Rightarrow\lambda_{max}=9.34\times 10^{-6}=934\ nm

So, the wavelength would be of around the Infrared part of the electromagnetic spectrum.

5 0
3 years ago
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