Answer:
Electric charge in the earth will be 
Explanation:
We have given that E = 116 N/C
Radius of the earth R = 6371 km = 6371000 m
We have to find the electric charge in the earth '
We know that electric field due to charge is given by
. here K is coulomb's constant
So 

So electric charge in the earth will be 
Answer:
I think the answer is C.
Explanation:
A primary source is a first hand account of an event while a secondary source is a retelling or second hand account meaning as many details will be prevalent.
Il existe troi types de rayons produits lors de la désintégration des éléments radioactifs:
-- "particules alpha" . . . noyaux d'hélium, composés chacun de 2 protons et 2 neutrons
-- "rayons bêta" ou "particules bêta" . . . flux d'électrons
-- "rayons gamma" . . . rayonnement électromagnétique avec les longueurs d'onde les plus courtes connues et l'énergie la plus élevée
Option 3 is the most reasonable
I hope this helped <3
Please give brainliest :)
<h2>The voltmeter reading will be 35.7 volt </h2>
Explanation:
The resistor 1000 ohm and 4000 ohm are connected in parallel .
Their combined resistance is supposed R₁
Thus
=
+
or R₁ = 800 ohm
Therefore the total resistance in circuit is = 2000 + 800 = 2800 ohm
Because these are in series .
We can find current flowing through the circuit I =
=
= 
here R is total resistance .
The potential difference across 1000 ohm =
x 1000 = 35.7 volt
Thus voltmeter reading will be 35.7 volt