Consider the displacement vectors Ā=(i +6j)m, B = (3i– 7j)m,
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Answer:
The net force acting on the person is 5.34 N acting upwards
Explanation:
The information given are;
Mass of the person = 55.0 kg
Density of the person = 1010 kg/m³
Body volume of the person = Mass/Density = 55/1010 = 0.0545 m³
Weight of the person = Mass × Gravity = 55 × 9.81 = 539.55 N↓
Where the density of water = 1000 kg/m³, we have;
Upthrust = weight of the water displaced = Mass of the water displaced × Gravity
Mass of the water displaced = Density of water × Volume of the water
Mass of the water displaced = Density of water × Body volume of the person
= 1000 × 0.0545 = 54.5 kg
The Upthrust = 54.5 × 9.81 = 534.21 N↑
Given that the net force, acting is the sum of the mass of forces acting on the person which are the weight acting downward and the upthrust acting upwards
We have;
F(Net) = 534.21↑ - 539.55↓ = 5.34 N↑
The net force acting on the person = 5.34 N upwards.
Answer:
Explanation:
For this case the situation is explained in the figure attached.
We can find the maximum radius r with the angle of incidence or critical angle (xi). If we have that the angle is higher than the light we will see a reflecting property. We can assume that the refracted angle for this case is 90 and if we use the following trigonometric property we have:
And if we solve for r we got:
The value of d on this case represent the depth of the watr d = 2.5 m
And we can find the value for the angle using the Snell's Law like this:
And we can use the arcsin in order to find the angle like this:
And now we can find the maximum radius replacing into
And we got:
