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Ber [7]
4 years ago
11

identify the Transformations that take place when you use an electric heater. begin with the transformations that take place in

a hydroelectric power plant and end with the energy produced by the heater and it's fan
Physics
1 answer:
galben [10]4 years ago
3 0
It is a electrical change
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Light travels in a straight line at a constant speed of 3,0 x 108 m/s for 4,1
zepelin [54]

Answer:

As the velocity of light is constant so the acceleration of the light is equal to zero.

a= dv/dt

Explanation:

4 0
3 years ago
10 turns of wire are closely wound around a pencil as shown in the figure. when measured using a scale as shown, the length of t
Mila [183]

Answer:

a. The thickness of the wire is 2.5 mm.

b. The wire is 0.25 cm thick.

Explanation:

Number of turns of the wire = 10

The length of total turns = 25 mm

a. The thickness of the wire can be determined by;

thickness of the wire = \frac{length of total turns}{number of turns}

                           = \frac{25}{10}

                           = 2.5 mm

Therefore, the wire is 2.5 mm thick.

b. To determine the thickness of the wire in centimetre;

10 mm = 1 cm

So that,

2.5 mm = x

x  = \frac{2.5}{10}

   = 0.25 cm

The wire is 0.25 cm thick.

8 0
3 years ago
A train starts from rest and travels for 5.0 s with a uniform acceleration of 1.5 m/s2. What is the final velocity of the train?
alexandr1967 [171]

Answer:

Final speed of the train is 7.5 m/s

Explanation:

It is given that,

Uniform acceleration of the train is, a = 1.5 m/s²

It starts from rest and travels for 5.0 s. We have to find the final velocity of the train. By using first equation of motion as :

v=u+at

Here, train starts from rest so, u = 0

v=0+1.5\ m/s^2\times 5\ s  

v = 7.5 m/s

So, the final velocity of the train is 7.5 m/s. Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
3. A certain wire, 3 m long, stretches by 1.2 mm when under tension of 200 N. By how much does
nikitadnepr [17]

Answer:

The extension of the second wire is   e_2 = 0.0024 \  m =  2.4 mm

Explanation:

From the question we are told that

    The length of the wire is L  = 3 \ m

     The elongation of the wire is  e =  1.2mm =  \frac{1.2}{1000} =  0.0012 m

        The tension is F  =  200 \ N

       The length of the second wire is  L_2   =  6 \ m

     

Generally the Young's modulus(Y) of this material is  

        Y  = \frac{stress}{strain }

Where stress =  \frac{F}{A}

    Where A is the area which is evaluated as  

           A = \pi r^2

  and   strain = \frac{extention}{length} =  \frac{e}{L}

   So

        Y  = \frac{\frac{F}{\pi r^2 } }{ \frac{e}{L}  }

Since the wire are of the same material Young's modulus(Y)  is constant

So we have  

              \frac{F * L }{r^2 e}  =  \pi * Y = constant

              F * L   =  constant   * r^2 e

Now the ration between the first and the second wire is

         \frac{F_1}{F_2}  * \frac{L_1}{L_2} =  \frac{r*2_1}{r^2}  *  \frac{e_1}{e_2}

Since tension , radius are constant

   We have

           \frac{L_1}{L_2} =   \frac{e_1}{e_2}

substituting values

          \frac{3}{6} =   \frac{0.0012}{e_2}

          0.5 e_2 =  0.0012

         e_2 = \frac{ 0.0012  }{0.5}

          e_2 = 0.0024 \  m =  2.4 mm

3 0
4 years ago
Number of complete 90.9 MHz radio waves over a 1.50 km distance
zimovet [89]
You could answer this right away IF you knew the length of each wave, right ?

Well,  Wavelength = (speed) / (frequency).

Speed = 3 x 10⁸ m/s  (the speed of light)
and
Frequency = 90.9 x 10⁶ Hertz.

So the length of each wave is  3 x 10⁸ / 90.9 x 10⁶  meters.

To answer the question, see how many pieces you have to cut
that 1.5 km into, in order for each piece to be 1 wavelength. 
It'll be

(1,500 meters) divided by (3 x 10⁸ meters/sec) / (90.9 x 10⁶ Hz)

To divide by a fraction, flip the fraction and then multiply:

(1500 meters) times (90.9 x 10⁶ Hz)/(3 x 10⁸ meters/sec)

=   454.5
5 0
4 years ago
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