Answer: the image distance is -18, 28 cm this means behind of the concave mirror. The image size is 2.2 higher that the original so it has 8.8 cm with the same orientation as original and it is a virtual imagen.
Explanation: In order to sove the imagen formation for a concave mirror we have to use the following equation:
1/p+1/q=1/f where p and q represents the distance to the mirror for the object and imagen, respectively. f is the focal length for the concave mirror.
replacing the values we obtain:
1/8.3+1/q=1/15.2
so 1/q=(1/15.2)-(1/8.3)=-54.7*10^-3
then q=-18.28 cm
The magnification is given by M=-q/p=-(-18,28)/8.3= 2.2
We also add a picture to see the imagen formation for this case.
Force of friction=75 N
Explanation:
we use Newton's second law of motion
F- Ff= ma
F = applied force=250 N
Ff= force of friction
a= acceleration= 5.83 m/s²
m= mass=30 kg
250- Ff= 30 (5.83)
Ff=250-30(5.83)
Ff=250-175
Ff=75 N
C it have two atoms for hydrogen
Answer:
Once we place a positive test at a point close to the sphere, we find that an electrostatic force is applied to the outside of the sphere. Therefore, at any point around the sphere, the electric field vector is radially outward.
Answer:
38.6 %
Explanation:
First of all, we have to calculate the final velocity of the block-bullet system. We can apply the law of conservation of momentum:

where
m = 0.15 kg is the mass of the bullet
u is the initial velocity of the bullet
M = 2.44 kg is the mass of the block
U = 0 is the initial velocity of the block (it is at rest)
v is the final velocity of the bullet+block
Solving for v,

The total initial kinetic energy of the system is just the kinetic energy of the bullet:

While the final kinetic energy of the block+bullet is:

So the fraction of kinetic energy lost is

And so, the fraction of kinetic energy left in the projectile after he flies off the block is
1 - 0.614 = 0.386 = 38.6 %