Answer:
6 m/s
Explanation:
Given that :
mass of the block m = 200.0 g = 200 × 10⁻³ kg
the horizontal spring constant k = 4500.0 N/m
position of the block (distance x) = 4.00 cm = 0.04 m
To determine the speed the block will be traveling when it leaves the spring; we applying the work done on the spring as it is stretched (or compressed) with the kinetic energy.
i.e
v = 6 m/s
Hence,the speed the block will be traveling when it leaves the spring is 6 m/s
Answer:
K. E = 6.0796 × 10^ -21 Joule
Explanation: see attachment
The sum of balanced forces will always be equal to zero.
Kinetic energy is the energy possessed by an object on motion. it is expressed as follows:
KE = 0.5mv^2
where m is the mass and v is the velocity of the object. We calculate as follows:
KE = 0.5mv^2
1.1x10^9 J = 0.5(8.0x10^4 kg) v^2
v = 165.83 m/s
Answer:
im sorry i cant help :(
Explanation: i hope someone does