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FromTheMoon [43]
3 years ago
13

A solid white substance A is heated strongly in the absence of air. It decomposes to form a new white crystalline substance B an

d a gas C. The gas ignites readily when combined with hydrogen gas and a liquid uncolored substance resulted. Based on these observations, can we determine whether solids A and B and gas C, are elements or compounds?
Chemistry
1 answer:
attashe74 [19]3 years ago
3 0

Answer:

A and B as well C are the compounds.

Explanation:

  • A seems to be a compound, very least, it appears to contain carbon and oxygen.
  • C seems to be a compound, containing respectively oxygen as well as carbon.
  • B isn't always described by that of the information provided, it is therefore presumably a compound because there are few components as white solid particles.

So that the above is the correct answer.

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during a chemical reaction when the products of that reaction require less potential energy describe what happens to the surroun
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Currently this lab is run qualitatively asking only for whether a solution is acidic, neutral, or basic. If quantitative informa
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Hence the PH range 7.6-8 can't be described using universal indicator.

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2 years ago
Comment on whether each of the following is a homogeneous mixture or a heterogeneous mixture: (a) air in a closed bottle, (b) ai
Colt1911 [192]

Explanation:

A mixture in which there is uniform distribution of solute particles into the solvent is known as a homogeneous mixture.

For example, sugar dissolved in water is a homogeneous mixture.

On the other hand, a mixture in which there is uneven distribution of solute particles into the solvent is known as a heterogeneous mixture.

For example, sand present in water is a heterogeneous mixture.

Comment on given situations will be as follows.

(a)   Air in a closed bottle - It is a homogeneous mixture because there will be even distribution of other gases that are present in air.

(b)   Air over New York City - It is a heterogeneous mixture because there will be presence of some dust particles, fog or smoke into the air. Distribution of all these particles will be uneven. This will make air over New York City heterogeneous in nature.

8 0
3 years ago
Calculate the molality of a 5.73 M ethanol (C2H5OH) solution whose density is 0.9327 g/mL.
Natalka [10]

Answer:

Molality = 8.57 m

Explanation:

Given data:

Molarity of solution = 5.73 M

density = 0.9327 g/mL

Molality of solution = ?

Solution:

Molality = moles of solute / kg of solvent.

Kg of solvent:

Mass of 1 L solution = density× volume

Mass of 1 L solution = 0.9327 g/mL × 1000 mL

Mass of 1 L solution = 932.7 g

Mass of solute:

Mass of 1 L = number of moles  × molar mass

Mass = 5.73 mol  × 46.068 g/mol

Mass = 263.97 g

Mass of solvent:

Mass of solvent = mass of solution - mass of solute

Mass of solvent = 932.7 g - 263.97 g

Mass of solvent = 668.73 g

In Kg = 668.73 /1000 = 0.6687 Kg

Molality:

Molality = number of moles of solute / mass of solvent in Kg

Molality = 5.73 mol /  0.6687 Kg

Molality = 8.57 m

4 0
2 years ago
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