Write the separation scheme for the isolation of triphenylmethanol from the reaction mixture once the reaction is complete. The
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Answer : The volume of carbon dioxide will be, 5.6122 L
Solution : Given,
Moles of LiOH = 0.5 moles
Molar mass of carbon dioxide = 44 g/mole
Density of carbon dioxide = 0.00196 g/ml
First we have to calculate the mass of carbon dioxide.
The balanced reaction will be,
From the reaction we conclude that
As, 2 moles of LiOH absorbs 44 grams of carbon dioxide
So, 0.5 moles of LiOH absorbs grams of carbon dioxide
Mass of carbon dioxide = 11 g
Density of carbon dioxide = 0.00196 g/ml
Now we have to calculate the volume of carbon dioxide.
Volume of carbon dioxide = 5612.24 ml = 5.6122 L (1 L = 1000 ml)
Therefore, the volume of carbon dioxide will be, 5.6122 L
