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levacccp [35]
3 years ago
12

Write the separation scheme for the isolation of triphenylmethanol from the reaction mixture once the reaction is complete. The

separation begins after the addition of HCl and water to the reaction and includes the column chromatography procedure to further purify crude triphenylmethanol isolated in the day 1 procedure.
Chemistry
1 answer:
Drupady [299]3 years ago
6 0

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The student plans to conduct a spectrophotometric analysis to determine the concentration of Cu2+(aq) in a solution. The solutio
Lelechka [254]

Answer:

The wavelength the student should use is 700 nm.

Explanation:

Attached below you can find the diagram I found for this question elsewhere.

Because the idea is to minimize the interference of the Co⁺²(aq) species, we should <u>choose a wavelength in which its absorbance is minimum</u>.

At 400 nm Co⁺²(aq) shows no absorbance, however neither does Cu⁺²(aq). While at 700 nm Co⁺²(aq) shows no absorbance and Cu⁺²(aq) does.

6 0
3 years ago
WILL RECIEVE MEDAL!If 1.2 kilograms of rust form on a bridge in five days, what should be the rate of reaction in grams per hour
serious [3.7K]
<span>Since the answer is in grams, kilograms must first be converted to grams. A kilogram is equivalent to 1000 grams. Therefore, multiply 1.2 kilograms by 1000 and you get 1,200 grams. Then, calculate the number of hours in 5 days. Each day is 24 hours and 24 hours multiplied by 5 days equals 120 hours. Lastly, since the answer is in grams per hour, divide 1,200 grams by 120 hours and the resultant rate of reaction is 10 g/hr.</span>
8 0
3 years ago
Finish this formula: Speed = _______ divided by time
Alexus [3.1K]

Answer:

Distance

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Speed= Distance/ Time

7 0
3 years ago
Read 2 more answers
How many moles of each reactant are needed to produce 3.60 x 10^2g ch3oh
zysi [14]
Methanol is prepared by reacting Carbon monoxide and Hydrogen gas,

                                   CO  +  2 H₂    →    CH₃OH

Calculating Moles of CO:
                                       According to equation,

             32 g (1 mole) of CH₃OH is produced by  =  1 Mole of CO
So,
             3.60 × 10² g of CH₃OH is produced by  =  X Moles of CO

Solving for X,
                       X  =  (3.60 × 10² g × 1 Mole) ÷ 32 g

                       X  =  11.25 Moles of CO

Calculating Moles of H₂:
                                       According to equation,

             32 g (1 mole) of CH₃OH is produced by  =  2 Mole of H₂
So,
             3.60 × 10² g of CH₃OH is produced by  =  X Moles of H₂

Solving for X,
                       X  =  (3.60 × 10² g × 2 Mole) ÷ 32 g

                       X  =  22.5 Moles of H₂

Result:
            3.60 × 10² g of CH₃OH
is produced by reacting 11.25 Moles of CO and 22.5 Moles of H₂.
3 0
4 years ago
What is the solute and solvent in roundup
olga nikolaevna [1]

Answer:

solute is that we disolve in solvent

solvent is in which we dissolve solute

8 0
3 years ago
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