Answer:
D = 9sin(2π(t + a)/24) + 45
Step-by-step explanation:
Let's find the average temperature;
(54 + 36)/2 = 45°
Amplitude = 54 - 45 = 9
From the wave equation, we can write the temperature as;
D = 9sin(2π(t + a)/24) + 45
Where;
D is the temperature
t is the time in hours after midnight
a is a "phase" that is used to set the time at which temperature(D) occurs
To solve this problem you must apply the proccedure shown below:
1. You have the following angle given in the problen above:
-230°
2. Then, to f<span>ind the least positive angle measurement that is coterminal with -230°, you must add 360°, as below:
coterminal angle=-230°+360°
coterminal angle=130°
3. Therefore, as you can see, the answer is: 130°</span>
Answer:
$100 increase
Step-by-step explanation:
500 x 20%
= $100 increase
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°