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3 years ago

Write the chemical symbols for three different atoms or atomic anions with 35 electrons.

1 answer:

4 0

Bromine atom, Br has 35 electrons
In Se there are 34 electrons and if it gain one electron and get negative charge then it has 35 electrons. So the symbol of anion wit 35 electrons is
Se⁻ has 35 electrons
<span>Another anion, no longer solid as quickly as back is As</span>²⁻
<span>As has 33 electrons and the two negatives shows now it has 35 electrons.</span>

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(will give brainliest) show your work. How many grams of Copper(I) nitrate, CuNO3 are required to produce 88.0 grams of aluminum

ValentinkaMS [17]

Based on the stoichiometry of the reaction, 156.114 g of CuNO3 are required to produce 88.0 grams of aluminum nitrate, Al(NO3)3.

<h3>What is stoichiometry of a reaction?</h3>

The stoichiometry of a reaction is the molar ratio in which reactants combine to form products.

The stoichiometry of the reaction shows that 6 moles of copper (i) nitrate produces 2 moles of aluminium nitrate.

molar mass of Copper(I) nitrate, CuNO3 = 126 g

molar mass of aluminum nitrate, Al(NO3)3 = 213 g

88.0 g of aluminum nitrate, Al(NO3)3 = 88.0/213 moles = 0.413 moles

0.413 moles of Al(NO3)3 will be produced by 0.413 ×6/3 = 1.239 moles of CuNO3

Mass of 1.239 moles of CuNO3 = 1.239 × 126 = 156.114 g of CuNO3

Therefore, 156.114 g of CuNO3 are required to produce 88.0 grams of aluminum nitrate, Al(NO3)3.

Learn more about stoichiometry at: brainly.com/question/16060223

Therefore, 156.114 g of CuNO3

4 0

2 years ago

Give the nuclear symbol for the isotope of gallium, ga, that contains 40 neutrons per atom. Replace the question marks with the

Cerrena [4.2K]

The nuclear symbol of an element have three parts namely:

the symbol of an element
mass number of the element
atomic number of the element

The general representation is as:

$_{Z}^{A}X$

where X is the chemical symbol of the element, A is mass number of the element that is total number of neutrons and protons in the nucleus of an atom, and Z is atomic number of the element that is number of protons in the atom.

Element = Gallium, $Ga$ (given)

Number of neutrons = 40 (given)

Let the nuclear symbol be $_{?}^{?}Ga$ . So, we need to determine the values of "?" in the symbol.

Atomic number of Gallium, $Ga$ = 31

Since, atomic number = Number of protons.

So, number of protons of Gallium, $Ga$ = 31

Mass number = number of protons + number of neutrons

Substituting the values:

Mass number = $31+40 = 71$

So, the nuclear symbol is $_{31}^{71}Ga$ .

7 0

4 years ago

At what phase of the cell cycle does the genetic material double?

natka813 [3]

There are the four phases of the cell cycle. M, G1, S and G3. And in S (Synthesis) phase genetic material is doubled.

3 0

3 years ago

what pressure will be needed to reduce the volume of 77.4 l of helium at 98.0 kpa to a volume of 60.0 l? 76 kpa 126 kpa

nekit [7.7K]

The system follow the Boyle's Law:

$P_1\cdot V_1 = P_2\cdot V_2\ \to\ P_2 = \frac{P_1\cdot V_1}{V_2} = \frac{98\ kPa\cdot 77.4\ L}{60.0\ L} = \bf 126.4\ kPa$

6 0

3 years ago

How many milliliters o a 0.2% solution o a skin test antigen must be used to prepare 4 mL o a solution containing 0.04 mg/mL o t

Klio2033 [76]

Answer:

0.08 mL

Explanation:

The solution of the skin test has a concentration of 0.2% (w/v), which means that there are 0.2 g of the antigen per 100 mL of the solution. If a new solution will be done using it, then this solution will be diluted, and the mass of the antigen added must be the same in the volume taken and at the diluted solution.

The mass is the concentration (in g/mL) multiplied by the volume of the solution (in mL), so, if m is the mass, C the concentration, V the volume, 1 the initial solution, and 2 the diluted:

m1 = m2

C1*V1 = C2*V2

Where

C1 = 0.2 g/100 mL = 0.002 g/mL

V1 = ?

C2 = 0.04 mg/mL = 0.00004 g/mL

V2 = 4 mL

0.002*V1 = 0.00004*4

V1 = 0.08 mL

5 0

4 years ago