This question can be simply solved by using heat formula,
Q = mCΔT
Q = heat energy (J)
m = Mass (kg)
C = Specific heat capacity (J / kg K)
ΔT = Temperature change (K)
when water freezes, it produces ice at 0°C (273 K)
hence the temperature change is 25 K (298 K - 273 K)
C for water is 4186 J / kg K or 4.186 J / g K
By applying the equation,
Q = 456 g x 4.186 J / g K x 25 K
= 47720.4 J
= 47.72 kJ
hence 47.72 kJ of heat energy should be removed.
It varies with container, temperature, pressure and amount of gas. But, the volume occupied by a gas at a fixed temperature and pressure remains constant which is 22.4 L for 1 mole at STP.
Answer:
As the description in the question shows, Kaley is taking careful and regular measurements. Hence, her experimental method is correct.
Kaley has also developed a hypothesis and the experiment she conducted is also valid hence there is no problem in these steps.
There is no mistake being done by her in depicting the results of the experiment.
Hence, the only thing which we can say is missing from the experiment is the past researches which scientists might have made on this topic.
Explanation:
Answer:
im pretty sure they heat up
Explanation:
as they use energy to go from solid to liquid to gas, they need heat to do so as they have a melting and boiling point
Answer:
P₂ = 1.0 atm
Explanation:
Boyles Law problem => P ∝ 1/V at constant temperature (T).
Empirical equation
P ∝ 1/V => P = k(1/V) => k = P·V => for comparing two different case conditions, k₁ = k₂ => P₁V₁ = P₂V₂
Given
P₁ = 1.6 atm
V₁ = 312 ml
P₂ = ?
V₂ = 500 ml
P₁V₁ = P₂V₂ => P₂ = P₁V₁/V₂ =1.6 atm x 312 ml / 500ml = 1.0 atm
