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3 years ago

Which property would radon most likely have? A. It is stable. B. It is a solid. C. It is flammable. D. It is silver in color.

Chemistry

2 answers:

Ivenika [448]3 years ago

7 0

Answer: option A) it is stable.

Travka [436]3 years ago

4 0

Answer: option A) it is stable.


Justification:


Radon (Rn) has atomic number 86. The electron distribution leads to the most stable configuration: the outermost shell (valence shell) is 6s² 6p⁶. That means that it has 8 valence electrons and, therefore, this shell is full. It will not accept more electrons ans will try to keep all of the ones it has.

This is the typical configuration of a noble gas. They are all in the group 18 of the periodic table (the last column). So, as the other noble gases, He, Ne, Ar, Kr, and Xe, Rn is very stable.

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Given that NASA needs 151,200 g of Oxygen (O2) per person for a mission, how many grams of water (H2O) does NASA need to ship to

IgorC [24]

this is so ez,

ok so here what u'll do after u balance the equation:

1. convert grams of oxygen to moles of oxygen.

2. convert moles of oxygen to moles of water

3. convert moles of water to grams of water.

4. bOOm... that's your answer

as follows:

2H2O(l)===>2H2(g)+O2(g)

1. 151200(g)/16(g/mol)=9540 moles of O2

2. 9450 moles of O2 × 2 moles of H2O =18900 moles of H2O

3. 18900 moles of H2O × 10g/mol = 189000g of H2O is required.

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4 years ago

You are conducting a plant growth experiment and need to generate a solution with growth factor, auxin or indole-3-acetic acid.

Yuki888 [10]

Answer:

7,01 g of indole-3-acetic acid

Explanation:

The milimolar concentration (mM) is defined as the ratio of milimoles per Liter of solution. 400mM means 400mmoles / L that is the same of 0,4mol / L

100mL are 0,1L. Using these values:

0,1L × (0,4mol / L ) = 0,04moles of indole-3-acetic acid.

As the MW of the molecule is 175,2 g/mol:

0,04mol × (175,2g / mol) = 7,01 g of indole-3-acetic acid

Thus, you need 7,01 g of indole-3-acetic acid to generate your solution.

I hope it helps!

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4 years ago

A sample of raw mining ore contains a hydrated salt called copper sulfate tetrahydrate, CuSO4.4H2O, along with other impurities.

julsineya [31]

Answer:

88.5 % of the raw ore is CuSO4*4H2O

Explanation:

Step 1: Data given

Mass of the ore = 10.854 grams

Mass of water = 2.994 grams

Step 2: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 2.994 grams / 18.02 g/mol

Moles H2O = 0.166 moles

Step 3: Calculate moles CuSO4*4H2O

For 1 mol CuSO4*4H2O we have 4 moles H2O

For 0.166 moles H2O we have 0.166/4 = 0.0415 moles CuSO4*4H2O

Step 4: Calculate mass CuSO4*4H2O

Mass CuSO4*4H2O = moles * molar mass

Mass CusO4*4H2O = 0.0415 moles * 231.67 g/mol

Mass CuSO4*4H2O = 9.61 grams

Step 5: Calculate mass % of CuSO4*4H2O

Mass % = (9.61 grams / 10.854 grams )*100 %

Mass % = 88.5 %

88.5 % of the raw ore is CuSO4*4H2O

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4 years ago

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kirza4 [7]

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natta225 [31]

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3 years ago