This equation is one of the most useful in classical physics. It is a concise statement of Isaac Newton's<span> Second Law of Motion, holding both the proportions and vectors of the Second Law. It translates as: The net force on an object is </span>equal<span> to the </span>mass<span>of the object multiplied by the </span>acceleration<span> of the object.</span>
When the object slides across the rough surface some of its potential energy will be lost to friction.
<h3>Conservation of mechanical energy</h3>
The law of conservation of mechanical energy states that the total mechanical energy of an isolated system is always constant.
M.A = P.E + K.E
When the object slides across the rough surface, some of the potential energy of the object will be converted into kinetic energy while the remaining potential energy will be converted into thermal energy due to frictional force of the rough surface.
P.E = K.E + thermal energy
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The assume that goes with the inquiry demonstrates the wavelenghts of the photons transmitted by Balmer arrangement change , from vitality levels (n) 3, 4, 5, and 6 to the vitality level (n) 2, in hydrogen particles.
These are the values shown in the figure
Transition wavelength of the photon emitted
nm
from n=3 to n=2 656<------ this is the value requested
from n=4 to n=2 486
from n=5 to n=2 434
from n=6 to n=2 410
The wavelength of a photon discharged from the n = 3 shell in hydrogen is the primary information of the table, i.e 656 nm.
Using the conversion factor from nm to m that results is :
656 nm * 1 m / (10^9 nm) = 656 * 10 ^ -9 m.
Hope this helps
The work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.
<h3>What is work done?</h3>
Work done is equal to product of force applied and distance moved.
Work = Force x Distance
Given is a block with a weight of 620 N is pulled up at a constant speed on a very smooth ramp by a constant force. The angle of the ramp with respect to the horizontal is θ = 23.5° and the length of the ramp is l = 14.1 m.
From the Newton's law of motion,
ma =F-mg sinθ =0
So, the force F = mg sinθ
Plug the values, we get
F = 620N x sin 23.5°
F = 247.224 N
Work done by motor is W= F x d
The force is equal to the weight F = mg
So, W = 247.224 x 14.1
W = 3.486 kJ
Thus, the work done by the force in pulling the block all the way to the top of the ramp is 3.486 kJ.
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