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Alchen [17]
3 years ago
11

Distance between the two place is 35 kilometers . If two persons start running towards each other from these two place with a sp

eed of 3 kilometers per hour and 4 kilometers per hour at 7.a.m . At what time do they meet​
Physics
1 answer:
pashok25 [27]3 years ago
7 0

The first person = A

The second one = B

velocity of A = 3 km / h

velocity of B = 4 km / h

Distance of A = 3t

Distance of B = 35 - 4t

At what time do they meet?

3t = 35 - 4t

7t = 35

t = 5 hours

7 a.m. + 5 hours = 12 p.m.

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Alenkasestr [34]

The distance an object falls, from rest, in gravity is

                         D  =  (1/2) (G) (T²)

                        'T' is the number seconds it falls.

In this problem,

                         0.92 meter = (1/2) (9.8) (T²)

Divide each side by  4.9 :   0.92 / 4.9 = T²

Take the square root
of each side:                          √(0.92/4.9) = T

                                                  0.433 sec = T    

The horizontal speed doesn't make a bit of difference in
how long it takes to reach the floor.  BUT ... if you want to
know how far from the table the pencil lands, you can find
that with the horizontal speed.

The pencil is in the air for  0.433 second.
In that time, it travels
                                   (0.433s) x (1.4 m/s) = 0.606 meter

from the edge of the table.
 
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3 years ago
A plane drops a rubber raft to the survivors of a shipwreck. The plane is flying at a height of 1960 m and with a speed of 109 m
Korolek [52]

In this case the rubber raft has horizontal and vertical motion.

Considering vertical motion first.

We have displacement  s = ut +\frac{1}{2}at^2, u = Initial velocity, t = time taken, a = acceleration.

In vertical motion

    s = 1960 m, u = 0 m/s, a = 9.81 m/s^2

    1960 = 0*t+\frac{1}{2} *9.81*t^2\\ \\ t = 20 seconds

So raft will take 20 seconds to reach ground.

Now considering horizontal motion of raft

u = 109 m/s, t = 20 s, a = 0m/s^2

So s = 109*20+\frac{1}{2} *0*20^2 = 2180 m

So shipwreck was 2180 meter far away from the plane when the raft was dropped.

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Suppose you were asked to find the torque about point p due to the normal force n in terms of given quantities. which method of
igomit [66]

Answer:

T=Lnsin\alpha

Please check the attached

Explanation:

The torque can simply be calculated by multiplying the length of the rod by the perpendicular force n as shown in the attached figure.

Note that sin90=1

T=Lsin\alpha(nsin90)

T=Lsin\alphaxn

T=Lnsin\alpha

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Question: What was his initial velocity?

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