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2 years ago

A loaf bread has a mass of 500 g and volume of 12.0 cm3. what is the density of the bread

Chemistry

1 answer:

pychu [463]2 years ago

5 0

41.6g/cm3 would be the density of the bread

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On the addition of HI

victus00 [196]

Answer:

$CH_3-CH(I)-CH(CH_3)-CH_3$

$I-CH_2-CH_2-CH(CH_3)-CH_3$

Explanation:

Given the compound $CH_2=CH-CH(CH_3)-CH_3$

The steps of reaction:

$HI \longrightarrow H^+ + I^-$

$CH_2=CH-CH(CH_3)-CH_3 + H^+ \longrightarrow CH_3-CH^+-CH(CH_3)-CH_3$

But this intermediate product has a resonance:

$CH_3-CH^+-CH(CH_3)-CH_3 \longleftrightarrow C^+H_2-CH2-CH(CH_3)-CH_3$

The reaction with I-

$CH_3-CH^+-CH(CH_3)-CH_3 + I^- \longrightarrow CH_3-CH(I)-CH(CH_3)-CH_3$

$C^+H_2-CH2-CH(CH_3)-CH_3 + I^- \longrightarrow I-CH_2-CH_2-CH(CH_3)-CH_3$

8 0

3 years ago

What is the mass (in g) of 0. 935 mol of acetone CH3COCH3 the molar mass of acetone is 58. 08 g∙mol^–1.

Ray Of Light [21]

Answer:

54.30 grams acetone

Explanation:

(0. 935 mol)*(58.08 g/mole) = 54.30 grams acetone

4 0

9 months ago

Read 2 more answers

How many total electrons can the p orbitals hold? A. 6 B. 2 C. 10 D. 3

mars1129 [50]

Answer:

A. 6

Explanation:

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8 0

2 years ago

Read 2 more answers

Name the components of stainless steel

tatuchka [14]

Explanation:

Composition of Stainless Steel

Steel is an alloy of iron and carbon. Stainless steels are steels containing at least 10.5% chromium, less than 1.2% carbon and other alloying elements

6 0

2 years ago

Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th

WINSTONCH [101]

Answer: The standard enthalpy change of the reaction is coming out to be -16.3 kJ

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]$

We are given:

$\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ$

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

6 0

3 years ago