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aleksley [76]
3 years ago
15

Potassium metal reacts with water according to the following balanced equation.

Chemistry
1 answer:
aivan3 [116]3 years ago
8 0

Answer: 1 mole

Explanation:

One mole reacts because there is a 1:1 ratio between the potassium and water at the beginning of the equation. 2K+2H2O has a 1 to 1 ratio. If one potassium reacts there is one h2o that also reacts.

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8 0
3 years ago
Someone please help me with this one :)
Crazy boy [7]
I think it is the answer choice B
4 0
3 years ago
Consider the total ionic equation below.
Tpy6a [65]

Answer:

The net ionic equation is

Ba²⁺ + CO₃²⁻ → BaCO₃(s)

Explanation:

The chemical reaction described is given as

Ba²⁺ + 2NO₃⁻ + 2Na⁺ + CO₃²⁻ → BaCO₃(s) + 2Na⁺ + 2NO₃⁻

The net ionic equation is obtained by eliminating the ions that appear on both sides of the equation.

And those ions are 2Na⁺ and 2NO₃⁻.

This is a double displacement reaction in which BaNO₃ (aq) reacts with Na₂CO₃ (aq) to form BaCO₃ (s) and NaNO₃ (aq).

The aqueous solutions exist in ionic forms in the reaction and in the net ionic equation, ioms that appear on both sides of the overall equation obviously cancel out.

Hope this Helps!!!

4 0
4 years ago
Read 2 more answers
A reaction in which A, B, and C react to form products is first order in A, second order in B, and zero order in C. a. Write a r
iragen [17]

Answer:

a. r = k. [A]¹. [B]².[C]⁰

b. 3

c. 2

d. 4

e. 1

f. 8

Explanation:

A reaction in which A, B, and C react to form products is first order in A, second order in B, and zero order in C.

a. Write a rate law for the reaction.

r = k. [A]¹. [B]².[C]⁰

where,

r is the <em>rate of the reaction</em>

k is the <em>rate constant</em>

[X]ⁿ are the <em>molar concentrations</em> of each reactant raised to its <em>reaction order</em>

b. What is the overall order of the reaction?

The overall order of reaction is the sum of the individual orders of reaction, that is, 1 + 2 + 0 = 3.

c. By what factor does the reaction rate change if [A] is doubled (and the other reactant concentrations are held constant)?

If A is doubled, then:

r' = k. [2A]¹. [B]².[C]⁰= 2 k. [A]¹. [B]².[C]⁰ = 2 . r

The factor is 2.

d. By what factor does the reaction rate change if [B] is doubled (and the other reactant concentrations are held constant)?

If B is doubled, then:

r' = k. [A]¹. [2B]².[C]⁰ = 4. k. [A]¹. [B]².[C]⁰ = 4 . r

The factor is 4.

e. By what factor does the reaction rate change if [C] is doubled (and the other reactant concentrations are held constant)?

If C is doubled, then:

r' = k. [A]¹. [B]².[2C]⁰ = 1. k. [A]¹. [B]².[C]⁰ = 1 . r

The factor is 1.

f. By what factor does the reaction rate change if the concentrations of all three reactants are doubled?

r' = k. [2A]¹. [2B]².[2C]⁰ = 2.4.1.k. [A]¹. [B]².[C]⁰ = 8 .r

The factor is 8.

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3 years ago
Which metalloid has three valence electrons? boron arsenic silicon lithium<br><br><br> HElp PLEase
Sever21 [200]

Answer:

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Explanation:

First, locate the metalloids on the periodic table. (First picture) The metalloids are in the yellow section. Next, remember that the group your element is in determines its valence electrons. For example, group 17/7A has 7 valence electrons. Look at the group numbers above each column on the periodic table to find out which metalloid is the answer. In this case, we need to look at 13/3A since we know that this metalloid has three valence electrons. Not all  periodic tables will be labeled with the 3A part, so remember that groups 13 and over have the amount of valence electrons after you take out the one in front. For example, group 16 has 6 valence electrons because I removed the one in front of it. Now your options should be limited down to boron because we know that it is in the yellow section in group 13.

3 0
3 years ago
Read 2 more answers
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