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Natali [406]
3 years ago
5

In the following reaction, 24 g of CH4 react with 96 g of Oz to form 66 g of CO2

Physics
1 answer:
Brut [27]3 years ago
8 0

Answer:

54 g

Explanation:

Mass is conserved.  Mass of reactants = mass of products.

24 g + 96 g = 66 g + x

x = 54 g

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What is Newton's third law?
harina [27]
For every actions there is an equal and opposite reaction.
3 0
3 years ago
Read 2 more answers
1. Two vectors have magnitudes 6 & 8 units, respectively. Find the maximum &
defon

Answer:

<em>The maximum magnitude of their resultant is 14 units, and the minimum is 2 units</em>

Explanation:

<u>Resultant Vectors</u>

When two or more vectors are added or subtracted, the resultant vector can be found by considering their magnitudes and directions.

Two vectors applied to the same point can produce a result that can vary from being completely collaborative or completely opposite.

If two vectors act in a collaborative form, their magnitudes are added and the result has the maximum possible magnitude. If they act in opposite directions, the result has the minimum possible magnitude.

Thus, being 6 and 8 units the magnitudes of the vectors, the maximum magnitude of their resultant is 14 units, and the minimum is 2 units.

5 0
3 years ago
Can you please solve this for me urgently want to make sure if my answers are correct?
MA_775_DIABLO [31]

Answer:

<u>Resolving</u><u> </u><u>horizontally</u><u>.</u> :

\sum d_{x} =  - (17.0 \cos 20.0) - (11.0 \cos 35.0) + (30.0 \cos 50.0) + 0 \\  { \underline{d _{x} =  -  5.702 \: m}} \\  \\  \sum d _{y} = (17.0 \sin 20.0) + 12.0 - (11.0  \sin 35.0) - (30.0 \sin 50.0) \\ { \underline{d _{y}  =  - 11.476 \: m}}

therefore, for resultant:

d =  \sqrt{ {d _{y} }^{2} + d _{x}  {}^{2}  }

substitute:

d =  \sqrt{ {( - 5.702)}^{2} +  {( - 11.476)}^{2}  }  \\  \\ d =  \sqrt{164.211}  \\  \\ { \boxed{ \boxed{ \bf{d = 12.8 \: m}}}}

6 0
2 years ago
The kicker now kicks the ball with the same speed as in the number of 4,but at 60.0°from the horizontal or 30.0° from the vertic
Shkiper50 [21]

Answer:

i) 0.7

ii) 1.39

iii) 0.6

Next time, when compiling a Physics question, ensure you put the unit of each measurement.

Explanation:

i) T = time of flight =   \frac{2uSin(A)}{g}

where u = speed = 4, A = 60 and  g = acceleration due to gravity = 10 (It is a constant);

Subsituting the values, we have: T = \frac{2(4)Sin(60)}{10} = 0.7

ii) distance travel = Range =  R = \frac{u^{2}Sin(2A) }{g}

where u = speed = 4, A = 60 and  g = acceleration due to gravity = 10 (It is a constant);

Subsituting values, we have: R = \frac{4^{2}Sin(2*60) }{10} = 1.39

iii) Maximum Height = H = \frac{u^{2}(Sin(A))^{2}  }{2g}

where u = speed = 4, A = 60 and  g = acceleration due to gravity = 10 (It is a constant);

Subsituting values, we have: \frac{4^{2}(Sin60)^{2}  }{2*10} = 0.6

4 0
2 years ago
A classroom is about 3 meters high, 20 meters wide and 30 meters long. If the density of air is 1.29 kg/m3, what is the mass of
Deffense [45]

Answer:

the mass of the air in the classroom = 2322 kg

Explanation:

given:

A classroom is about 3 meters high, 20 meters wide and 30 meters long.

If the density of air is 1.29 kg/m3

find:

what is the mass of the air in the classroom?

density = mass / volume

where mass (m) = 1.29 kg/m³

volume = 3m x 20m x 30m = 1800 m³

plugin values into the formula

  1.29 kg/m³   =  <u>      mass    </u>

                             1800 m³

mass =  1.29 kg/m³  ( 1800 m³ )

mass = 2322 kg

therefore,

the mass of the air in the classroom = 2322 kg

8 0
3 years ago
Read 2 more answers
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