Answer:
¹⁰₄Be —> ¹⁰₃Li + ⁰₋₁β
Explanation:
To know which equation is unbalanced, we shall compare the mass number and atomic number of the reactant and product together. This is illustrated below:
¹²¹₅₀Sn —> ⁰₋₁β + ¹²¹₅₁Sb
121 = 0 + 121
121 = 121
50 = –1 + 51
50 = 51
Thus the above equation is balanced
¹⁹⁰₇₈Pt —> ¹⁸⁶₇₆Os + ⁴₂α
190 = 186 + 4
190 = 190
78 = 76 + 2
78 = 78
Thus, the above equation is balanced
¹⁰₄Be —> ¹⁰₃Li + ⁰₋₁β
10 = 10 + 0
10 = 10
4 = 3 + (–1)
4 = 3 – 1
4 = 2
Thus, the above equation is unbalanced.
²³⁸₉₂U —> ⁴₂α + ²³⁴₉₀Th
238 = 4 + 234
238 = 238
92 = 2 + 90
92 = 92
Thus, the above equation is balanced.
From the illustrations made above, only ¹⁰₄Be —> ¹⁰₃Li + ⁰₋₁β
Is unbalanced.
Percentage Weight-in-volume is defined as the <em><u>number of grams of a solute in a 100 ml (milliliters) solution.</u></em>
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<u>Percentage Weight-in-volume</u> can tell us about the <em>degree of concentration of a given solution.</em>
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The solute can be <em>crystalline or non-crystalline in nature.</em>
<em></em>
The <u>number of grams of glucose</u> present in a <u>5% glucose solution</u> is 5 grams.
- This question is based on a Percentage Weight-in-volume. The formula states that:
a% of a glucose solution =<u> a grams of glucose in a 100 mL solution</u>
Hence, 5% glucose solution = 5 grams of glucose / 100 mL solution
Therefore, the <u>number of grams of glucose</u> present in a <u>5% glucose solution</u> is 5 grams.
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Answer:
I think so
Explanation:
It would provide an extra energy boost with lower sugars. Students bring drinks to school anyways so it would be nice to offer some that aren't as detrimental.
The role<span> of a </span>decomposer<span> is to decompose or break down dead matter in the environment. Plants make their own food by the process of photosynthesis and also produce (hence the name) food for other </span>consumers<span>. Without </span>producers<span> an </span>ecosystem<span> could not sustain itself.</span>
I believe your answer Is C. An ammonia molecule has a trigonometrical pyramidal shape. Figure C has a <span>has a trigonometrical pyramidal shape.</span>
I hope I help