Answer:
A) E° = 4.40 V
B) ΔG° = -8.49 × 10⁵ J
Explanation:
Let's consider the following redox reaction.
2 Li(s) +Cl₂(g) → 2 Li⁺(aq) + 2 Cl⁻(aq)
We can write the corresponding half-reactions.
Cathode (reduction): Cl₂(g) + 2 e⁻ → 2 Cl⁻(aq) E°red = 1.36 V
Anode (oxidation): 2 Li(s) → 2 Li⁺(aq) + 2 e⁻ E°red = -3.04
<em>A) Calculate the cell potential of this reaction under standard reaction conditions.</em>
The standard cell potential (E°) is the difference between the reduction potential of the cathode and the reduction potential of the anode.
E° = E°red, cat - E°red, an = 1.36 V - (-3.04 V) 4.40 V
<em>B) Calculate the free energy ΔG° of the reaction.</em>
We can calculate Gibbs free energy (ΔG°) using the following expression.
ΔG° = -n.F.E°
where,
n are the moles of electrons transferred
F is Faraday's constant
ΔG° = - 2 mol × (96468 J/V.mol) × 4.40 V = -8.49 × 10⁵ J
Answer:
Described by a redox reaction below
Explanation:
Iron(III) oxide is an ionic compound, since it consists of a metal, iron, and a nonmetal, oxygen.
Ionic compounds are formed when metals lose their valence electrons in order to have an octet in their previous shell and donate them to nonmetal atoms, so that nonmetals fill their outer shell to have an octet.
As a result, positive ions (cations) and negative ions (anions) are formed. When iron reacts with oxygen, the following reaction takes place:
This is a redox (oxidation–reduction) reaction, since we have electron loss and gain. Four iron atoms lose a total of 12 electrons to obtain a +3 charge in the final compound, while 3 oxygen molecules gain these 12 electrons to become 6 oxide anions with a -2 charge.
Utiliando las leyes de Newton encontraremos que la aceleración de Ana es -1.6 m/s^2.
La segunda ley de Newton dice que:
F = m*a
Fuerza es igual a masa por aceleración.
La tercera ley de Newton dice que cuando dos objetos interactuan, cadan objeto ejerce una fuerza de <u>igual magnitud pero opuesta direccion</u> en el otro.
Ahora veamos como aplicar esto.
Sabemos que la niña empuja al niño, asumamos que con una fuerza F.
Tendremos entonces la ecuación:
F = 20kg*(2m/s^2) = 40N
Y por la tercer ley de Newton, esta misma fuerza (pero en opuesta dirección) se aplica a la niña, entonces tendremos:
-40N = 25kg*a
-40N/25kg = a = -1.6 m/s²
La aceleración con la que retrosede la niña es -1.6 m/s²
Sí quieres aprender más, puedes leer:
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I think it’s A not sure though
The first step is to focus on the parent carbon chain:nonane. This indicates a carbon chain with 9 carbon atoms. From here, on the 4th carbon from one side, place a Br functional group; on the 2nd carbon, place a I functional group; on the 5th and 6th carbon, place a CH₃ (methyl) functional group to each. Lastly, complete the bonding with H atoms. The structure is shown in the attached picture.
