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Mars2501 [29]
3 years ago
9

RIGHT ANSWER GETS BRAINLIEST+5 STARS.

Physics
2 answers:
gogolik [260]3 years ago
8 0

Answer:

B) the decay rates of radioactive uranium and lead

Explanation:

As we know that when she found the substance it must have some fixed ratio of radioactive uranium and Lead in that substance.

Here since Uranium is radioactive substance so it will continuously convert into Lead and this ratio will change with time

So here we can say that the ratio of radioactive uranium and lead will depend on its decay rate

now to find the age of the substance we can find the present ratio of lead and uranium in that substance and then compare it with freshly prepared substance.

so by the formula

t = \frac{1}{\lambda}ln(\frac{N_0}{N})

we can find the age of the sample

insens350 [35]3 years ago
5 0

Answer:

B) the decay rates of radioactive uranium and lead

Explanation:

The radioactive decay is modeled using an exponential function with an essential parameter, namely the decay rate. The two rates (for urianium and lead) allow her to determine the number of years that passed since the time the zirconium was formed.

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A 75-m-long train begins uniform acceleration from rest. the the train has a speed of 23 m/s when it passes a railway worker tan
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acceleration a = 1.04 m/s2

Explanation:

Assume the train has a speed of 23m/s when the last car passes the railway workers. Once this happens the last car would have traveled a total distance of the 180m distance between the railway worker standing 180 m from where the front of the train started plus the 75m distance from the first car to the last car:

s = 75 + 180 = 255 m

We can use the following equation of motion to find out the distance traveled by the car:

v^2 - v_0^2 = 2aswhere v = 23 m/s is the velocity of the car when it passes the worker, v_0 = 0m/s is the initial velocity of the car when it starts, a m/s2 is the acceleration, which we are looking for.

23^2 - 0^2 = 2*a*255

510a = 529

a = 529 / 510 = 1.04 m/s^2

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Explanation:

hope it helps :))

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