The energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.
<h3>Change in energy level of the electron</h3>
When photons jump from a higher energy level to a lower level, they emit or radiate energy.
The change in energy level of the electrons is calculated as follows;
ΔE = Eb - Ef
ΔE = -2.68 eV - (-5.74 eV)
ΔE = 3.06 eV
Thus, the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.
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M1*V1 + M2*V2 = M1*V + M2*V.
1400*25 + 1800*20[180+40]=1400*V+1800*V.
Divide both sides by 100:
14*25 + 18*20[220o] = 14V + 18V.
350 + 360[220o] = 32V.
350 - 276-231i = 32V.
74 - 231i = 32V.
242.6[-72.2o] = 32V.
V = 7.6m/s[-72.2o]=7.6m/s[72o] S. of E.
Answer:
non-accelerated movement
velocity versus time a horizontal straight line.
distance versus time gives a horizontal straight line.
accelerated motion
graph of velocity versus time s an inclined line and the slope
graph of distance versus time is a parabola of the form
Explanation:
In kinematics there are two types of steely and non-accelerated movements
In a the velocity of the body is constant therefore a speed hook against time gives a horizontal straight line.
A graph of distance versus time is a straight line whose slope is the velocity of the body
x = v t
In an accelerated motion the velocity changes linearly with time, so a graph of velocity versus time is an inclined line and the slope is the value of the acceleration of the body
v = v₀ + a t
A graph of distance versus time is a parabola of the form
x =v₀ t + ½ a t²
