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MA_775_DIABLO [31]
4 years ago
7

A car is travelling at a constant speed of 26.5 m/s. Its tires have a radius of 72 cm. If the car slows down at a constant rate

to 11.7 m/s over 5.2 s, what is the magnitude of the angular acceleration of the tires during that time? (in rad/s^2)
Physics
1 answer:
maksim [4K]4 years ago
4 0

Answer:

Magnitude of angular acceleration = -3.95 rad/s²

Explanation:

Angular acceleration is the ratio of linear acceleration and radius.

That is

        \texttt{Angular acceleration}=\frac{\texttt{Linear acceleration}}{\texttt{Radius}}\\\\\alpha =\frac{a}{r}

Radius = 72 cm = 0.72 m

Linear acceleration is rate of change of velocity.

a=\frac{11.7-26.5}{5.2}=-2.85m/s^2

Angular acceleration

        \alpha =\frac{a}{r}=\frac{-2.85}{0.72}=-3.95rad/s^2

Angular acceleration = -3.95 rad/s²  

Magnitude =  3.95 rad/s²     

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The magnitude​ R, measured on the Richter​ scale, of an earthquake of intensity I is defined as Requalslog StartFraction Upper I
lapo4ka [179]

Answer:

R = 6.8

Explanation:

Given data:

Richter scaleR = log(\frac{I}{I_o})

where R - magnitude of earthquake of Richter scale

I - quake's intensity =  10^{6.8} \times I_o

I_o - minimum intensity earthquake

Plugging all information in the equation to get Richter's scale

R = log(\frac{10^{6.8} \times I_o}{I_o})

R = log(10^{6.8})

R = 6.8

6 0
3 years ago
2 equal charges are kept at x=a and x=-a. there can be only 1 point where the electric field will be 0? how, can anyone explain?
svet-max [94.6K]

Answer:

At the midpoint of the line joining the two equal charges

Explanation:

The midpoint of the line joining the two equal charges has equal distance from each charge. Since the charges are at x = a and x = -a, at the midpoint of the line joining the two equal charges, the magnitude of the electric field experienced as a result of each charge is the same. But these two fields are in opposite direction, hence the net resulting electric field would be equal to zero.

6 0
3 years ago
If you were to triple the size of the Earth (R = 3R⊕) and double the mass of the Earth (M = 2M⊕), how much would it change the g
EastWind [94]

Answer:

Decreased by a factor of 4.5

Explanation:

"We have Newton formula for attraction force between 2 objects with mass and a distance between them:

F_G = G\frac{M_1M_2}{R^2}

where G =6.67408 × 10^{-11} m^3/kgs^2 is the gravitational constant on Earth. M_1, M_2 are the masses of the object and Earth itself. and R distance between, or the Earth radius.

So when R is tripled and mass is doubled, we have the following ratio of the new gravity over the old ones:

\frac{F_G}{f_g} = \frac{G\frac{M_1M_2}{R^2}}{G\frac{M_1m_2}{r^2}}

\frac{F_G}{f_g} = \frac{\frac{M_2}{R^2}}{\frac{m_2}{r^2}}

\frac{F_G}{f_g} = \frac{M_2}{R^2}\frac{r^2}{m_2}

\frac{F_G}{f_g} = \frac{M_2}{m_2}(\frac{r}{R})^2

Since M_2 = 2m_2 and r = R/3

\frac{F_G}{f_g} = \frac{2}{3^2} = 2/9 = 1/4.5

So gravity would have been decreased by a factor of 4.5  

8 0
3 years ago
Suppose a car's standard tires are replaced with tires 1.30 times larger in diameter.(i) Will the car's speedometer reading be (
Nezavi [6.7K]

The answer is 1.30 times too low.

<h3>What is a speedometer reading?</h3>
  • According to the law, speedometers can never understate a vehicle's speed while never exceeding 110% of the real speed + 6.25 mph. Therefore, if you're traveling at 40 mph, your speedometer may display up to 50.25 mph, but it will never show a speed below 40 mph.
  • While the speedometer displays how fast your car is moving, the odometer displays how far it has traveled. According to Tetzlaff, the speedometer's accuracy in most cars, including Volkswagens, is typically within a few percentage points of actual speed.
  • A car's speedometer is a tool that displays the vehicle's speed. An odometer is yet another accessory connected to a speedometer. The car's odometer displays the distance driven. The speedometer, as we all know, displays the pace of every single moment.
  • Federal law prohibits speedometers from having an inaccuracy of more than 5% (usually stated as plus/minus 2.5% relative to the real speed), according to Dan Edmunds, an automotive engineer and director of vehicle testing at Edmunds.com.

The answer is 1.30 times too low.

To learn more about speedometers, refer to:

brainly.com/question/3397467

#SPJ4

5 0
2 years ago
What will happen to satellite if the linear speed is reduced?. give a reason for your answer​
cricket20 [7]

Explanation:

If the satellite is moving too quickly then the gravitational attraction between the Earth and the satellite is too weak to keep it in orbit. If this is the case, the satellite will move off into space. This occurs at speeds around or above 11,200 metres per second (m/s).

8 0
3 years ago
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