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sashaice [31]
3 years ago
9

Balance the reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1.

" H₂O₂ → H₂O + O₂
Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

2H₂O₂ → 2H₂O + O₂

Explanation:

H₂O₂ → H₂O + O₂

The above equation can be balance as illustrated below:

H₂O₂ → H₂O + O₂

There are 2 atoms of O on the left side and a total of 3 atoms on the right side. It can be balance by putting 2 in front of H₂O₂ and 2 in front of H₂O as shown below:

2H₂O₂ → 2H₂O + O₂

Now, the equation is balanced.

**** check ****

Element >>> Left Side >>> Right Side

H >>>>>>>>> 4 >>>>>>>>> 4

O >>>>>>>>> 4 >>>>>>>>> 4

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Sergeu [11.5K]

Answer:

nitric acid can be classified as a strong acid

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Explanation:

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3 years ago
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what happened when potassium chloride is added to silver nitrate solutions . there no reaction B two soluble salts are formed C
Mashutka [201]

Answer:

D. One soluble and one insoluble salts are formed

Explanation:

8 0
2 years ago
Which of the following buffers will be most effective at pH 9.25? Group of answer choices a mixture of 1.0 M HC2H3O2 and 1.0 M N
ludmilkaskok [199]

Answer:

The most effective buffer at pH 9.25 will be  a mixture of 1.0 M NH3 and 1.0 M NH4Cl

Explanation:

Step 1: Data given

pH of a buffer = pKa + log ([A-]/[Ha])

a mixture of 1.0 M HC2H3O2 and 1.0 M NaC2H3O2 (Ka for acetic acid = 1.8 x 10-5)

pH = -log( 1.8 * 10^-5) + log (1/1)

pH = -log( 1.8 * 10^-5)

pH = 4.74

a mixture of 1.0 M NaCN and 1.0 M KCN (Ka for HCN = 4.9 x 10-10)

pH = -log( 4.9 * 10^-10) + log (1/1)

pH = -log( 1.8 * 10^-5)

pH = 9.30

a mixture of 1.0 M HCl and 1.0 M NaCl

The solution made from NaCl and HCl will NOT act as a buffer.

HCl is a strong acid while NaCl is salt of strong acid and strong base which do not from buffer solutions hence due to HCl PH is less than 7.

a mixture of 1.0 M NH3 and 1.0 M NH4Cl (Kb for ammonia = 1.76 x 10^-5)

Ka * Kb = 1*10^-14

Ka = 10^-14 / 1.76*10^-5

Ka = 5.68*10^-10

pH = -log( 5.68*10^-10) + log (1/1)

pH = -log( 5.68*10^-10)

pH = 9.25

The most effective buffer at pH 9.25 will be  a mixture of 1.0 M NH3 and 1.0 M NH4Cl

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3 years ago
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Answer:

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2 years ago
Object A specific heat is 2.45 J/g C and object B specific heat is 0.82 J/g C. Which object will heat up more if they have the s
Artist 52 [7]

Answer: Object B will heat up more.

Explanation:

The formula for specific heat is as follows.

                  Q = m C \Delta T

Where,

                      Q = heat provided

                      m = mass

                      C = specific heat

            \Delta T = change in temperature

Now, both the objects have same mass and equal amount of heat is applied.

According to the formula, the equation will be as follows.

                      Q_{1} = Q_{2}

                  m C_{1}\Delta T = m C_{2}\Delta T_{2}

Cancel m from both sides, as mass is same. Therefore,

            C_{1} (T_{f} - T_{i})_A = C_{2}(T_{f} - T_{i})_B

Cancel out the initial temperature and put the values of specific heat, then the equation will be as follows.

             2.45 (T_{f})_A = 0.82(T_{f})_B

Therefore, from the above equation it can be concluded that the object with low specific heat will heat up more as its specific heat will be inversely proportional to its final temperature.

Hence, object B will heat up more.

                   


           

4 0
3 years ago
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