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MatroZZZ [7]
2 years ago
8

What is the amount of heat energy absorbed when 36 grams of ice at -20oC is melted to water at 0oC?

Chemistry
1 answer:
Ulleksa [173]2 years ago
3 0

Answer:

Q = 1461.6 J

Explanation:

Given data:

Mass of ice = 36 g

Initial temperature = -20°C

Final temperature = 0°C

Amount of heat absorbed = ?

Solution:

specific heat capacity of ice is 2.03 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT =  0°C - (-20°C)

ΔT = 20°C

Q = 36 g ×2.03 j/g.°C×20°C

Q = 1461.6 J

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I think that solute mass may be it can affect the rate of reaction, if you have more mass in a solute, you will also have more moles.

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How many grams of FeO would be needed to make 234.2 grams of Fe in the chemical reaction 4FeO = Fe3O4 + Fe? Show your work.
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The grams  of FeO  that would  be needed to make 234.2 grams  of Fe  is

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<u><em> calculation</em></u>

4 FeO → Fe₃O₄ +Fe

Step 1: find the  moles  of  fe

moles  =  mass /molar mass

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