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cricket20 [7]
3 years ago
12

What is denser kerosene, fuel oil, or butane

Chemistry
2 answers:
noname [10]3 years ago
5 0
It depends on the temperature and pressure.

Under the same conditions, kerosene has a higher density.

we know that because we can google it, but a good rule of thumb is that the longer carbon chain has more density.
frez [133]3 years ago
3 0
I'm not sure what type of fuel you're talking about. If you mean fossil fuel then kerosene has the highest density of all of the things you listed.
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Bakit mahalaga ang paghahanda ng pambansang badyet sa isang taon?​
Andreas93 [3]

Answer:

no lo sé chico ve a morir en un agujero

Explanation:

8 0
2 years ago
What causes water to become denser when it is carried to the poles by surface currents? increased temperature and increased sali
Anarel [89]

Answer:

The answer is decreased temperature and increased salinity

Explanation:

It is what is known as the thermohaline circulation

The thermohaline circulation moves the water slowly. This water moves mainly due to differences in its relative density. Much denser water sinks over water that is less dense. Two factors impact the density of seawater: temperature and salinity.

Cold water is denser than hot water:

-Water cools when it loses heat, it occurs at high latitudes.

-Water is heated when it receives energy from the sun, at low latitudes.

Saltier water is much denser than water that has less salt:

-Sea water becomes salty if the evaporation rate increases.

-Sea water becomes less salty if there is a water inlet over the sea.

3 0
2 years ago
Read 2 more answers
The half life of radon-222 is 3.8 days. How Much of a 100g sample is left after 15.2 days
professor190 [17]

Answer:  

6.2 g  

Explanation:  

In a first-order decay, the formula for the amount remaining after <em>n</em> half-lives is  

N = \frac{N_{0}}{2^{n}}  

where  

<em>N</em>₀ and <em>N</em> are the initial and final amounts of the substance  

1. Calculate the <em>number of half-lives</em>.  

If t_{\frac{1}{2}} = \text{3.8 da}  

n = \frac{t}{t_{\frac{1}{2}}} = \frac{\text{15.2 da}}{\text{3.8 da}}= \text{4.0}

2. Calculate the <em>final mass</em> of the substance.  

\text{N} = \frac{\text{100 g}}{2^{4.0}} = \frac{\text{100 g}}{16} = \text{6.2 g}

4 0
3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m
Bond [772]

Answer:

m_{H_2O}=4.86gH_2O

Explanation:

Hello,

In this case, the described chemical reaction is:

C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O

Best regards.

3 0
3 years ago
How does a physical change differ from a chemical change
inysia [295]

With a physical change you can actually see it change like ice turning into water, then with a chemical change you can't see it change, although within the molecules themselves they change which makes that possible.


Hope this helps!

6 0
3 years ago
Read 2 more answers
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