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Eddi Din [679]
4 years ago
10

Disturbances inside Earth’s core cause earthquakes. The starting point of the disturbance is called the epicenter. Why does the

amplitude of a seismic wave usually decrease as the wave moves away from the epicenter?
The waves lose energy in the form of heat.
The frequency of the waves continues to increase.
The wavelength of the waves continues to decrease.
The waves encounter entirely different mediums.
Physics
2 answers:
Sveta_85 [38]4 years ago
8 0

Answer:

The waves lose energy in the form of heat.

Explanation:

The waves of the earthquake loose power and energy due to an exchange in energy, friction between the mediums cause the earthquake to loose energy in form of heat, that makes the earthquake to be much more weak when the waves are traveling far than in the epicenter.

Serhud [2]4 years ago
4 0

The answer is; The waves encounter entirely different mediums

The amplitude is higher in highly elastic medium (rock) while the amplitude is lower is lessens elastic medium/rock. When the seismic waves meet a denser  medium the amplitude decreases (and the frequency increases). This effect resembles the refraction of light waves. The energy of the wave dissipates as it spreads over a large and larger area from the epicenter.


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Answer:

Explanation:

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6 0
3 years ago
Each piston of an engine makes a sharp sound every other revolution of the engine. How fast is a race car going if its eight-cyl
goldfiish [28.3K]

Answer:

93.75 m/s

Explanation:

Given:

The frequency of the sound = 750 Hz

The number of pistons making the sound = 8

Revolutions made by the engine = 2000 revolutions/ km

Thus,

the frequency of sound by 1 piston = 750 / 8  = 93.75 Hz

also, it is given that for every other revolution sound is made.

thus, for every 2 revolution sound is made

therefore,

Number of revolutions per second = 93.75 Hz × 2 = 187.5 rev/s

Now,

the speed of the car will be calculated as:

= Number of revolutions per second / Revolutions made by the engine

or

The speed of the car = \frac{187.5\ rev/s}{2000\ rev/km}

or

The speed of the car = 0.09375 km/s = 93.75 m/s

3 0
3 years ago
An athlete can twirl a baton so that it reaches an angular velocity of 12 rad/s from rest in 0.5 s. If the length of a uniform b
NikAS [45]

Answer:

The torque needed is 46.08 Nm

Explanation:

Given;

angular velocity, ω = 12 rad/s

time of motion, t = 0.5 s

length of the baton, r = 0.8 m

mass of the baton, 0.5 kg

The torque needed to  reach the angular velocity is given by;

τ = F x r

where;

F is the centripetal force of the baton

r is the length of the baton = radius of the circular motion of the baton

F_c =ma_c= \frac{mv^2}{r} = m\omega^2 r

Torque is given by;

\tau = F_c *r\\\\\tau = m \omega^2 r *r\\\\\tau = m \omega^2 r^2 \\\\\tau = (0.5)(12)^2(0.8)^2\\\\\tau = 46.08 \ N m

Therefore, the torque needed is 46.08 Nm

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What requirement must a force acting on a object satisfy in order for the object to undergo simple harmonic motion?
viktelen [127]

Answer:

Simple harmonic motion is the movement of a body or an object to and from an equilibrium position. In a simple harmonic motion, the maximum displacement (also called the amplitude) on one side of the equilibrium position is equal to the maximum displacement.

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6 0
3 years ago
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