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Mazyrski [523]
3 years ago
5

What is defined by force per unit area

Physics
2 answers:
sleet_krkn [62]3 years ago
7 0

Explanation:

<em>For</em><em>ce</em><em> </em><em>per</em><em> </em><em>uni</em><em>t</em><em> </em><em>area</em><em> </em><em>is</em><em> </em><em>call</em><em>ed</em><em> </em><em>Pres</em><em>sure</em><em>.</em>

FinnZ [79.3K]3 years ago
7 0

Answer:

Pressure

Explanation:

Let , us understand by a simple example. Let us apply some force into a needle into a cardboard what we observe , we saw that the needle get into the cardboard.

Now we will apply the same force with a water bottle into the same cardboard , now we noticed that it doesn't get buried into it.

In both examples we noticed that force applied in both the cases is equal but the surface area of the object in which force applied is different.

Here come the term pressure.

Pressure is defined as force applied per unit area.

Therefore , as area increases pressure also decreases . That's why bottle don't get buried but needle go through it.  

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An increase in which quantity will result in an increase in momentum?
Mkey [24]

Answer:

a. velocity.      PLATO USERS

Explanation:

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Given the position vector of the particle
Natali [406]

With position vector

\vec r(t)=(t+1)\,\vec\imath+(t^2-1)\,\vec\jmath+2t\,vec k

the particle then has velocity

\vec v(t)=\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=\vec\imath+2t\,\vec\jmath+2\,vec k

and acceleration

\vec a(t)=\dfrac{\mathrm d\vec v(t)}{\mathrm dt}=\dfrac{\mathrm d^2\vec r(t)}{\mathrm dt^2}=2\,\vec\jmath

Then t=1, then particle's velocity and acceleration are, respectively,

\vec v=\vec\imath+2\vec\jmath+2\,\vec k

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3 years ago
A number of compounds containing the heavier noble gases, and especially xenon, have been prepared. One of these is xenon hexafl
aalyn [17]

Answer:

The answer is "82.2 torr"

Explanation:

moles of Xe:

= \frac{0.06}{131.293} \\\\ =0.00045699313 \ \mol

moles of F_2:

= \frac{0.0274}{38} \\\\= 0.00072105263\ \  mol

moles of produced XeF_2:

= 0.00024

moles of left Xe:

= 0.00021

Calculate the Pressure:

= \frac{(0.08206\times 0.00024 \times 293)}{(.1)}   + \frac{(0.08206\times  0.00021 \times  293)}{(.1)} \\\\= 0.10819611 \ \ atm \\\\ = 0.10819611 \times  760 \\\\ = 82.2 \ \ torr

5 0
3 years ago
On one of the shelves in your physics lab is displayed an antique telescope. A sign underneath the instrument says that the tele
Vesna [10]

Answer:

The focal length fe of the eyepiece is <em>2.86 cm</em>

Explanation:

Since we are given the telescope's magnification and the length of the tube, we can use the expressions

<em>M = f_o/fe (1)</em> and

<em>l = f_o + fe   (2)</em>

where

  • M is the telescope's magnification
  • l is the length of the tube
  • fe is the focal length of the eye-piece

Rearranging equation (2) to make f_o the subject of the formula, we get

<em>f_o = l - fe</em>

Substituting the above equation into equation (1) we get

<em>M = (l - fe)/fe ⇒ fe = l/(M +1)</em>

<em>                      ⇒ fe = 60/(20 + 1)</em>

                     ⇒ <em>fe  = 2.86 cm</em>

4 0
4 years ago
Why is disagreement among scientists important to the progress of science? Facing disagreement forces scientists to prove their
mash [69]
Facing disagreement forces scientists to prove their theories more conclusively.
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