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ZanzabumX [31]
3 years ago
5

How many electrons move past a fixed reference point every t = 2.55 ps if the current is i = 7.3 μA ? Express your answer as an

integer.
Engineering
1 answer:
iris [78.8K]3 years ago
4 0

Answer:

116.3 electrons

Explanation:

Data provided in the question:

Time, t = 2.55 ps = 2.55 × 10⁻¹² s

Current, i = 7.3 μA = 7.3 × 10⁻⁶ A

Now,

we know,

Charge, Q = it

thus,

Q = (7.3 × 10⁻⁶) × (2.55 × 10⁻¹²)

or

Q = 18.615 × 10⁻¹⁸ C

Also,

We know

Charge of 1 electron, q = 1.6 × 10⁻¹⁹ C

Therefore,

Number of electrons past a fixed point = Q ÷ q

= [ 18.615 × 10⁻¹⁸ ] ÷ [ 1.6 × 10⁻¹⁹ ]

= 116.3 electrons

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(40 points) Program the following sorting algorithms: InsertionSort, MergeSort, and QuickSort. There are 9 test les uploaded for
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Answer:

Explanation:

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#include<stdlib.h>

#include<stdio.h>

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int i, j, k;

int n1 = m - l + 1;

int n2 = r - m;

 

int L[n1], R[n2];

for (i = 0; i < n1; i++)

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R[j] = arr[m + 1+ j];

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k = l;

while (i < n1 && j < n2)

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{

arr[k] = L[i];

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arr[k] = R[j];

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}

while (i < n1)

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arr[k] = L[i];

i++;

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arr[k] = R[j];

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void mergeSort(int arr[], int l, int r)

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void printArray(int A[], int size)

{

int i;

for (i=0; i < size; i++)

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printf("\n");

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int main()

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int arr[1000] = {0};

int arr_size =0;

int data;

char file1[20];

strcpy(file1,"data.txt");

FILE *fp;

fp = fopen(file1,"r+");

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perror("Unable to open file");

return -1;

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fscanf (fp, "%d", &data);    

arr[arr_size]=data;

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fscanf (fp, "%d", &data);  

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arr_size++;    

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printf("Given array is \n");

printArray(arr, arr_size);

mergeSort(arr, 0, arr_size - 1);

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3 years ago
Oil of density 780 kg/m3 is flowing at a velocity of 20 m/s at the atmospheric pressure in a horizontal cylindrical tube elevate
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Answer:

radius = 0.045 m

Explanation:

Given data:

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velocity = 20 m/s

height = 25 m

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we have now

E = kinetic energy+ potential energy +  flow work

E = \dot m ( \frac{v^2}{2] +  zg + p\nu)

E = \dot m( \frac{v^2}{2] +  zg + p_{atm} \frac{1}{\rho})

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solving for flow rate

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solving for d

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