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inessss [21]
3 years ago
7

List all possible fracture mechanisms under which the unidirectional composites fail. Briefly explain and describe the related m

aterial behavior for each mechanism.
It is seen that the composite longitudinal strength and stiffness and transverse stiffness are improvements over the corresponding matrix properties due to the presence of fibers. However, a unidirectional composite subjected to transverse loads exhibit lower strength ranges than does the matrix material. Why? Use diagrams or equations as needed.
Describe the damage accumulation process in cross-ply laminates ([0/90/90/0]) under longitudinal loading step by step. Also, estimate the elastic modulus of the composite using EL and ET (for longitudinal and transverse modulus of each ply) assuming all plies are of same thickness.
Engineering
1 answer:
professor190 [17]3 years ago
7 0

Answer:

Ususushehehehhuuiiïbbb

Explanation:

Yyshehshehshshsheyysysueueue

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Consider uniaxial extension of a test specimen. It has gauge length L = 22 cm (the distance between where it is clamped in the t
Katena32 [7]

Answer:

A) 4800.6 N

B) 0.2255 mm/min

C) 8.6792 inches

Explanation:

Given data :

gauge Length = 22 cm = 220 mm

cross section diameter/thickness = 1.8 mm

young's modulus ( E ) = 205 GPa

Ultimate tensile strength ( σu ) = 420MPa

Time = 2 mins

A) what force would fracture the specimen

σU = Ff /A

where A (area) = thickness * width ( unknown )  hence we assume a width of 6.35 mm

Ff = σU × A =  420 * 1.8 * 6.35 = 4800.6 N

B) calculate the strain rate

Ultimate tensile strength ( σU ) = εE

ε = σU / E = 420/205000 = 0.00205

also  ε ​​​​​​ =  ΔL / Li = ( Lf - Li) / Li = (Lf / Li) - 1

 therefore  ε ​​​​​​ + 1 = (Lf / Li) = 1 + 0.00205 = 1.00205

 Li = gauge length = 220 mm

Hence :  Lf = 1.00205 × gauge length =  1.00205 * 220 =  220.451 mm

  strain rate

(Lf - Li) / Time = (0.451) / 2 min = 0.2255 mm/min

C) Elongation in inches prior to fracture

ΔL = ε × Li = 0.451 mm

Lf = 220 mm + 0.451 mm = 220.451 mm =  8.6792 inches

3 0
3 years ago
Which of the following is most likely to require changes to existing zoning laws?
oksano4ka [1.4K]

Answer:

Adaptive reuse

thats it thankyou

8 0
3 years ago
What are the two safety precautions taken before driving a car​
nydimaria [60]

<em>Answer:</em>

<h3><em>1. Check mirrors</em></h3><h3><em>2. Put on your seat belt</em></h3>

<em>Explanation:</em>

<em>1. Checking your mirrors are very important because if someone screwed with them then it can mess up your driving. </em>

<em />

<em>2. Putting on your seat belt is a law so you must put it on and it can save your life one day. </em>

7 0
4 years ago
How to plot 0.45 gradation chart for sieve analysis ?
LekaFEV [45]

Answer:

532235w3r35w3r

Explanation:

ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?ysis ?

5 0
3 years ago
A proposed piping and pumping system has 20-psig static pressure, and the piping discharges to atmosphere 160 ft above the pump.
larisa86 [58]

Answer: (B) 100

Explanation:

Given that;

Pstatic = 20 psig , hz = 160ft, hf = 20ft

Now total head will be;

T.h = hz + hf

T.h= 160 + 20

T.h = 180ft

Minimum pressure = Psatic + egh

we know that specific weight of water is 62.4 (lb/ft3)

so

P.min = (20 bf/in² ) + (62.4 b/ft³ × 180 fr

P.min = (20 bf/in² ) + ( 62.4 × 180 × 1 ft²/144 in²)

P.min = 20 + 78

P.min = 98 lbf/in²

Therefore the minimum pressure rating (psi) of the piping system is most nearly B) 100

7 0
4 years ago
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