1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inessss [21]
3 years ago
7

List all possible fracture mechanisms under which the unidirectional composites fail. Briefly explain and describe the related m

aterial behavior for each mechanism.
It is seen that the composite longitudinal strength and stiffness and transverse stiffness are improvements over the corresponding matrix properties due to the presence of fibers. However, a unidirectional composite subjected to transverse loads exhibit lower strength ranges than does the matrix material. Why? Use diagrams or equations as needed.
Describe the damage accumulation process in cross-ply laminates ([0/90/90/0]) under longitudinal loading step by step. Also, estimate the elastic modulus of the composite using EL and ET (for longitudinal and transverse modulus of each ply) assuming all plies are of same thickness.
Engineering
1 answer:
professor190 [17]3 years ago
7 0

Answer:

Ususushehehehhuuiiïbbb

Explanation:

Yyshehshehshshsheyysysueueue

You might be interested in
A 1.5-m-long aluminum rod must not stretch more than 1 mm and the normal stress must not exceed 40 MPa when the rod is subjected
Pavlova-9 [17]

Answer:

the required diameter of the rod is 9.77 mm

Explanation:

Given:

Length = 1.5 m

Tension(P) = 3 kN = 3 × 10³ N

Maximum allowable stress(S) = 40 MPa = 40 × 10⁶ Pa

E = 70 GPa = 70 × 10⁹ Pa

δ = 1 mm = 1 × 10⁻³ m

The required diameter(d)  = ?

a) for stress

The stress equation is given by:

S = \frac{P}{A}

A is the area = πd²/4 = (3.14 × d²)/4

S = \frac{P}{(\frac{3.14*d^{2} }{4}) }

S = \frac{4P}{{3.14*d^{2} } }

3.14*S*{d^{2}} = {4P}

{d^{2}} =\frac{4P}{3.14*S}

d=  \sqrt{\frac{4P}{3.14*S} }

Substituting the values, we get

d=  \sqrt{\frac{4*3*10^{3} }{3.14*40*10^{6} } }

d=  \sqrt{\frac{12000 }{125600000  } }

d=  \sqrt{9.55*10^{-5}  }

d = (9.77 × 10⁻³) m

d = 9.77 mm

b) for deformation

δ = (P×L) / (A×E)

A = (P×L) / (E×δ) = (3000 × 1.5) / (1 × 10⁻³ × 70 × 10⁹) = 0.000063

d² = (4 × A) / π = (0.000063 × 4) / 3.14

d² = 0.0000819

d = 9.05 × 10⁻³ m = 9.05 mm

We use the larger value of diameter = 9.77 mm

3 0
3 years ago
Giải giúp mình câu này được không ạ.em cảm ơn
sp2606 [1]

Answer:

çâdßèöñbvjsjaushdhshs

4 0
3 years ago
Need help with these 3 questions pls help
Burka [1]

Answer:

Explanation:

First one is passion i think

second one is true im not sure

Third one is Time managaemant

Hope this helps!

8 0
3 years ago
Calculate KI for a rectangular bar containing an edge crack loaded in three-point bending where P=35.0 kN, W=50.8 mm, B=25 mm, a
Katyanochek1 [597]

Answer:

K_{I}=5.21 MPa\sqrt{m}

Explanation:

given data

Load P = 35 kN

Width of bar W = 50.8 mm

Breadth of bar B = 25 mm

Ratio of crack length to width α = a/W = 0.2

solution

we get here KI for a rectangular bar that is express as

K_{I} = \frac{6P}{BW}Y\sqrt{\pi a}   ................................1

here Y is the geometrical function

so

Y = \frac{1.12+\alpha (3.43\alpha -1.89)}{1-0.55\alpha}

Y = \frac{1.12+0.2(3.43\times 0.2-1.89)}{1-0.55\times 0.2}  

Y = \frac{0.8792}{0.89}  

Y = 0.9878

so put here value in equation 1

K_{I} = \frac{6\times 35\times 10^{3}}{0.025\times 0.0508}\times 0.9878\times \sqrt{3.1415\times (0.2\times 0.0508)}    

K_{I} = 165354.33\times 10^{3}\times 0.9878\times 0.0319

K_{I} = 5210.45 × 10³  Pa\sqrt{m}  

K_{I} = 5.21 MPa \sqrt{m}

5 0
3 years ago
Two balanced Y-connected loads in parallel, one drawing 15kW at 0.6 power factor lagging and the other drawing 10kVA at 0.8 powe
NemiM [27]

Answer:

(a) attached below

(b) pf_{C}=0.85 lagging

(c) I_{C} =32.37 A

(d) X_{C} =49.37 Ω

(e) I_{cap} =9.72 A and I_{line} =27.66 A

Explanation:

Given data:

P_{1}=15 kW

S_{2} =10 kVA

pf_{1} =0.6 lagging

pf_{2}=0.8 leading

V=480 Volts

(a) Draw the power triangle for each load and for the combined load.

\alpha_{1}=cos^{-1} (0.6)=53.13°

\alpha_{2}=cos^{-1} (0.8)=36.86°

S_{1}=P_{1} /pf_{1} =15/0.6=25 kVA

Q_{1}=P_{1} tan(\alpha_{1} )=15*tan(53.13)=19.99 ≅ 20kVAR

P_{2} =S_{2}*pf_{2} =10*0.8=8 kW

Q_{2} =P_{2} tan(\alpha_{2} )=8*tan(-36.86)=-5.99 ≅ -6 kVAR

The negative sign means that the load 2 is providing reactive power rather than consuming  

Then the combined load will be

P_{c} =P_{1} +P_{2} =15+8=23 kW

Q_{c} =Q_{1} +Q_{2} =20-6=14 kVAR

(b) Determine the power factor of the combined load and state whether lagging or leading.

S_{c} =P_{c} +jQ_{c} =23+14j

or in the polar form

S_{c} =26.92°

pf_{C}=cos(31.32) =0.85 lagging

The relationship between Apparent power S and Current I is

S=VI^{*}

Since there is conjugate of current I therefore, the angle will become negative and hence power factor will be lagging.

(c) Determine the magnitude of the line current from the source.

Current of the combined load can be found by

I_{C} =S_{C}/\sqrt{3}*V

I_{C} =26.92*10^3/\sqrt{3}*480=32.37 A

(d) Δ-connected capacitors are now installed in parallel with the combined load. What value of capacitive reactance is needed in each leg of the A to make the source power factor unity?Give your answer in Ω

Q_{C} =3*V^2/X_{C}

X_{C} =3*V^2/Q_{C}

X_{C} =3*(480)^2/14*10^3 Ω

(e) Compute the magnitude of the current in each capacitor and the line current from the source.

Current flowing in the capacitor is  

I_{cap} =V/X_{C} =480/49.37=9.72 A

Line current flowing from the source is

I_{line} =P_{C} /3*V=23*10^3/3*480=27.66 A

8 0
3 years ago
Other questions:
  • The 150-lb man sits in the center of the boat, which has a uniform width and a weight per linear foot of 3 lb>ft. Determine t
    9·1 answer
  • a metal coin has certain properties that can be measured.which property of a coin is different on the moon that is on earth?
    6·1 answer
  • Steam at 320°C flows in a stainless steel pipe (k 5 15 W/m·K) whose inner and outer diameters are 5 cm and 5.5 cm, respectively.
    6·1 answer
  • A pendulum has an oscillation frequency (T) which is assumed to depend upon its length (L), load mass (m) and the acceleration o
    8·1 answer
  • Drivers ED. An inflamed stomach and a poorly-functioning pancreas __________.
    6·1 answer
  • State 3 advantages and 3 disadvantages of unit rate contract​
    10·1 answer
  • While discussing diagnostic procedures: Technician A says that after the visual inspection has been performed, the DTCs should b
    14·1 answer
  • Catalytic converters reduce the engine's tailpipe emissions of unburned hydrocarbons and carbon monoxide and
    6·2 answers
  • when it comes to game mechanics, what is the most universal mechanic that is present in virtually every computer game that you c
    9·1 answer
  • Explain why it is important to model the context of a system that is being developed. Give two examples of possible errors that
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!