Answer:
(a) 2.39 MPa (b) 3.03 kJ (c) 3.035 kJ
Explanation:
Solution
Recall that:
A 10 gr of air is compressed isentropically
The initial air is at = 27 °C, 110 kPa
After compression air is at = a450 °C
For air, R=287 J/kg.K
cv = 716.5 J/kg.K
y = 1.4
Now,
(a) W efind the pressure on [MPa]
Thus,
T₂/T₁ = (p₂/p₁)^r-1/r
=(450 + 273)/27 + 273) =
=(p₂/110) ^0.4/1.4
p₂ becomes 2390.3 kPa
So, p₂ = 2.39 MPa
(b) For the increase in total internal energy, is given below:
ΔU = mCv (T₂ - T₁)
=(10/100) (716.5) (450 -27)
ΔU =3030 J
ΔU =3.03 kJ
(c) The next step is to find the total work needed in kJ
ΔW = mR ( (T₂ - T₁) / k- 1
(10/100) (287) (450 -27)/1.4 -1
ΔW = 3035 J
Hence, the total work required is = 3.035 kJ
Answer:
1. B. False
2. B. False
3. A. True
4. B. False
5. A. True
6. A. True
7. A. True
Explanation:
1. B. False
The relation of Reynolds' number, Reₓ to boundary layer thickness δ at a point x is given by the relation

That is the boundary layer thickness is inversely proportional to the square root of the Reynolds' number so that if the Reynolds' number were to increase, the boundary layer thickness would decrease
Therefore, the correct option is B. False
2. B. False
From the relation

As the outer flow velocity increases, the boundary layer thickness diminishes
3. A. True
As the viscous force is increased the boundary layer thickness increases
4. B. False
Boundary layer thickness is inversely proportional to velocity
5. A. True
The boundary layer model developed by Ludwig Prandtl is a special case of the Navier-Stokes equation
6. A. True
Given a definite boundary layer thickness, the curve representing the boundary layer thickness is a streamline
7. A. True
The boundary layer approximation by Prandtl Euler bridges the gap between the Euler (slip boundary conditions) and Navier-Stokes (no slip boundary conditions) equations.
Answer:
I don't necessarily know the context of the text you are talking about, but a flameless candle could represent how there no more light in the author's life, which could represent a lack of happiness or a loss. Hope this helps!
Explanation:
Answer:
A turbo blade has the best features from both other types of blade. The continuous, serrated edge makes for fast cutting while remaining smooth and clean. They are mostly used to cut a variety of materials, such as tile, stone, marble, granite, masonry, and many other building materials.
Explanation: