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Alona [7]
3 years ago
10

1) Rephrase the objective. (limit 2 sentences). Give a brief explanation of the concepts of linear motion, its characteristics a

nd relationship between position, velocity and time for constant velocity and uniformly accelerated motion. (limit 8-10 sentences).
Physics
2 answers:
JulijaS [17]3 years ago
4 0

Answer:

  • The linear motion is the motion in one dimension or in a straight line.

For a linear motion the magnitude of, distance is equal to displacement, speed is equal to the velocity because the body moves only in one direction.

<u>For constant velocity motion:</u>

There is no change in velocity of the body with respect to time and hence we have zero acceleration of the moving body.

The relation is given as,

x=v.t

where;

x= position of the object after time t, moving with uniform velocity v.

<u>For a motion with uniform acceleration:</u>

In this case the acceleration of the motion remains same irrespective of the position of the object. So, the rate of change in velocity is same throughout all the points of motion of the object.

The relation is given as:

s=ut+\frac{1}{2}a.t^2

where:

s= displacement of the body moving with initial velocity u, having a uniform acceleration a, over a time span t.

Softa [21]3 years ago
3 0

Answer:

When an object moves in a straight line, it is said to be in linear motion. By Newton's first law of motion, a body tends to be in rest or motion in a straight line until a net non-zero force acts on it.

Rate of change of position with respect to time is known as velocity. Uniformly accelerated motion refers to the motion where the rate of change of velocity with respect to time is constant.

Kinematic equations can be used to measure different aspects of a linear motion:

v = u + a t

s = u t + 0.5 a t²

v²= u² + 2 a s

where, u is initial velocity, v is final velocity, a is acceleration, t is time and s is displacement.

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4 years ago
A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end when it
Tems11 [23]

Answer:

5.4 ms⁻¹

Explanation:

Here we have to use conservation of energy. Initially when the stick is held vertical, its center of mass is at some height above the ground, hence the stick has some gravitational potential energy. As the stick is allowed to fall, its rotates about one. gravitational potential energy of the stick gets converted into rotational kinetic energy.

L = length of the meter stick = 1 m

m = mass of the meter stick

w = angular speed of the meter stick as it hits the floor

v = speed of the other end of the stick

we know that, linear speed and angular speed are related as

v = r w\\w = \frac{v}{r}

h = height of center of mass of meter stick above the floor = \frac{L}{2} = \frac{1}{2} = 0.5 m

I = Moment of inertia of the stick about one end

For a stick, momentof inertia about one end has the formula as

I = \frac{mL^{2} }{3}

Using conservation of energy

Rotational kinetic energy of the stick = gravitational potential energy

(0.5) I w^{2} = mgh\\(0.5)(\frac{mL^{2} }{3}) (\frac{v}{L} )^{2} = mgh\\(0.5)(\frac{v^{2} }{3}) = gh\\(0.5)(\frac{v^{2} }{3}) = (9.8)(0.5)\\v = 5.4 ms^{-1}

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