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Alona [7]
3 years ago
10

1) Rephrase the objective. (limit 2 sentences). Give a brief explanation of the concepts of linear motion, its characteristics a

nd relationship between position, velocity and time for constant velocity and uniformly accelerated motion. (limit 8-10 sentences).
Physics
2 answers:
JulijaS [17]3 years ago
4 0

Answer:

  • The linear motion is the motion in one dimension or in a straight line.

For a linear motion the magnitude of, distance is equal to displacement, speed is equal to the velocity because the body moves only in one direction.

<u>For constant velocity motion:</u>

There is no change in velocity of the body with respect to time and hence we have zero acceleration of the moving body.

The relation is given as,

x=v.t

where;

x= position of the object after time t, moving with uniform velocity v.

<u>For a motion with uniform acceleration:</u>

In this case the acceleration of the motion remains same irrespective of the position of the object. So, the rate of change in velocity is same throughout all the points of motion of the object.

The relation is given as:

s=ut+\frac{1}{2}a.t^2

where:

s= displacement of the body moving with initial velocity u, having a uniform acceleration a, over a time span t.

Softa [21]3 years ago
3 0

Answer:

When an object moves in a straight line, it is said to be in linear motion. By Newton's first law of motion, a body tends to be in rest or motion in a straight line until a net non-zero force acts on it.

Rate of change of position with respect to time is known as velocity. Uniformly accelerated motion refers to the motion where the rate of change of velocity with respect to time is constant.

Kinematic equations can be used to measure different aspects of a linear motion:

v = u + a t

s = u t + 0.5 a t²

v²= u² + 2 a s

where, u is initial velocity, v is final velocity, a is acceleration, t is time and s is displacement.

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Dahasolnce [82]

Answer:

See the explanation.

Explanation:

The speeds of sound depend upon the temperature of the medium. As the temperature increased in the afternoon, the speed of sound increases. Then the time taken by reflected sound will be less than 0.1 sec in the afternoon. And to hear an echo the time gap between an original sound and reflected sound must be at least 0.1 sec. That is why the student could not hear the echo at all in the afternoon.

7 0
3 years ago
How much heat is needed to melt a 3 kg block of cheddar cheese initially at room tmperature of 24 degrees C? (assume the melting
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8 0
4 years ago
A disk has 128 tracks of 32 sectors each, on each surface of eight platters. The disk spins at 3600 RPM and takes 15 ms to move
Serga [27]

Answer:

the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms

Explanation:

 Given the data in the question;

first we determine the rotational latency

Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms

To get the longest time, lets assume the sector will be found at the last track.

hence we will access all the track, meaning that 127 transitions will be done;

so the track changing time = 127 × 15 = 1905 ms

also, we will look for the sectors, for every track rotations that will be done;

128 × 8.33 = 1066.24 ms

∴The Total Time = 1066.24 ms + 1905 ms

Total Time = 2971.24 ms

Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms

7 0
3 years ago
Fragments of molecules that have at least one electron available for bonding are called
Luda [366]
They are called radicals.................
5 0
3 years ago
An attacker at the base of a castle wall 3.95 m high throws a rock straight up with speed 5.00 m/s from a height of 1.60 m above
s344n2d4d5 [400]

Answer:

a) No

b) the rock must have a minimum initial speed of 6.79m/s for it to reach the top of the building.

Explanation:

Given:

Height of the wall = 3.95m

Initial height = 1.60m

Initial speed = 5.00m/s

distance between the initial height and wall top = 3.95 - 1.60 = 2.35m

Using the formula;

v^2 = u^2 + 2as ....1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance travelled

From equation 1

s = (v^2 - u^2)/2a ...2

Since the rock t moving up,

the acceleration = -g = -9.8m/s2

s = maximum height travelled

v = 0 (at maximum height velocity is zero)

Substituting into equation 2

s = (0 - 5^2)/(2×-9.8) = 1.28m

Therefore, the maximum height is 1.28 from his initial height Which is less than the 2.35m of the wall from his initial height. So the rock will not reach the top of the wall

b) Using equation 1:

u^2 = v^2 - 2as

v = 0

a = -9.8m/s

s = 2.35m. (distance between the initial height and wall top)

u^2 = 0 - 2(-9.8 × 2.35)

u^2 = 46.06

u = √46.06

u = 6.79m/s

Therefore, the rock must have a minimum initial speed of 6.79m/s

8 0
4 years ago
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