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3 years ago

Why were the rings of Uranus not observed directly from telescopes on the ground on Earth? How were they discovered?

Physics

1 answer:

leonid [27]3 years ago

6 0

Answer:Explained below.

Explanation:

Uranus rings is made up of jet black, coal-like particles in small bands, making them difficult to perceive from Earth.This indicates that they are probably composed of a mixture of the ice and a dark material. The nature of material is dismal, but it might be some organic compounds greatly darkened by the charged particle irradiation from the Uranian magnetosphere. Rings were discovered by using a infrared telescope throughout the occultation of a star as Uranus passed in front of it. The light from the star dimmed many times before it was obstructed by the disk of Uranus and subsequently, showing the presence of various distinct rings.

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Who is wwe universal champion

mina [271]

Answer:

Roman reigns

Explanation:

is the wwe universal hampion

7 0

3 years ago

A block of wood measuring 2.75 cm x 4.80 cm x 7.50 cm has a mass of 84.0 g. will the block of wood sink or float in water?

KIM [24]

The volume of the block of wood is given by length × width ×height
= 2.75 × 4.80 × 7.5
= 99 cm³
Density is given by mass/volume
Thus = 84.0 g/ 99 cm³
= 0.848 g/cm³
Hence; since the block is less dense than water (1 g/cm³) it will float

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2 years ago

Dallas says that any change in velocity is directly proportional tothe time interval over which the change took place. Dana says

Anna35 [415]

Answer:

e. Only(a) and (b) above are correct

Explanation:

Impulse

= Fx t = m ( v-u )

v-u = change in velocity

F x t = mass x change in velocity

change in velocity = F t / mass

=a t

change in velocity ∝ t ( time ) , if a is constant

dv = a_avg dt

∫dv = a_avg ∫dt

v-u = a_avg t

change in velocity ∝ t ( time )

So both (a) and (b) are correct.

7 0

2 years ago

que 2. Why do we keep frequency constant instead of keeping vibrating length constam second law of vibrating string?

ella [17]

Answer:

The second law of a vibrating string states that for a transverse vibration in a stretched string, the frequency is directly proportional to the square root of the string's tension, when the vibrating string's mass per unit length and the vibrating length are kept constant

The law can be expressed mathematically as follows;

$f = \dfrac{1}{2\cdot l} \cdot \sqrt{\dfrac{T}{m} }$

The second law of the vibrating string can be verified directly, however, the third law of the vibrating string states that frequency is inversely proportional to the square root of the mass per unit length cannot be directly verified due to the lack of continuous variation in both the frequency, 'f', and the mass, 'm', simultaneously

Therefore, the law is verified indirectly, by rearranging the above equation as follows;

$m = \dfrac{1}{ l^2} \cdot \dfrac{T}{4\cdot f^2} }$

From which it can be shown that the following relation holds with the limits of error in the experiment

m₁·l₁² = m₂·l₂² = m₃·l₃² = m₄·l₄² = m₅·l₅²

Explanation:

8 0

2 years ago

What is the speed between reflected ray and the incident ray

Korvikt [17]

Answer:

The speed is the same as long as the reflection is regular.

Explanation:

This is because in regular reflection, the angle of incidence is equal to the angle of reflection in accordance with the second law of reflection.

Since speed of light depends on the angle of the light ray it makes with the reflecting surface, the speed is the same

7 0

3 years ago