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3 years ago

Why were the rings of Uranus not observed directly from telescopes on the ground on Earth? How were they discovered?

Physics

1 answer:

leonid [27]3 years ago

6 0

Answer:Explained below.

Explanation:

Uranus rings is made up of jet black, coal-like particles in small bands, making them difficult to perceive from Earth.This indicates that they are probably composed of a mixture of the ice and a dark material. The nature of material is dismal, but it might be some organic compounds greatly darkened by the charged particle irradiation from the Uranian magnetosphere. Rings were discovered by using a infrared telescope throughout the occultation of a star as Uranus passed in front of it. The light from the star dimmed many times before it was obstructed by the disk of Uranus and subsequently, showing the presence of various distinct rings.

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In the following diagrams the larger vector has a magnitude of 10, and the smaller

Anton [14]

the sum of vectors with the Pythagorean theorem allows us to find that the maximum magnitude occurs for the case:

d) the two vectors are parallel

Vectors are physical quantities that have modulus and direction, for example: force, velocity, acceleration, etc.

Vector algebra has defined the sum, the product by a scalar and by a vector. The modulus and the direction of the resulting vector must be encoded.

The sum of two quantities is done using the Pythagorean theorem

c² = a² + b²

where c is the resultant called hypotenuse, a and b are the summing vectors called legs; trigonometry is used for the direction.

Let's apply this expression to the present case

a, b) perpendicular vectors

c² = a² + b²

c = $\sqrt{6^2+10^2}$

c = 11.7

the magnitude is the same in both cases, changing the direction of the vector

c) Antiparallel vectors

For this case the vectors are collinear, so the sum reduces to the algebraic addition

c = a-b

c = 6 -10

c = -4

d) parallel vectors

c = a + b

c = 4 + 10

c = 14

We can see that the vectors addition gives their maximum and minimum values when the vectors are collinear.

In conclusion using the vectors addition we find that the correct answer is

d) the two vectors are parallel

learn more about vector addition here:

brainly.com/question/15074838

6 0

2 years ago

Learning Goal: To understand the nature of a sound wave, including its properties: frequency, wavelength, loudness, pitch, and t

Lady_Fox [76]

Answer:

Sound wave is a longitudinal wave that propagates in a medium

Explanation:

Part A: (C) Sound wave is propagation of pressure fluctuations in a medium.

Part B: (C) Pressure fluctuations travel along the direction of propagation of the sound wave.

Part C: (A) Yes air play a role in the propagation of the human voice from one end of the lecture hall to the other.

5 0

3 years ago

Which is an example of colloid

bulgar [2K]

Colloid mixtures can be solids, liquids, or gases. EX- Would include, butter, milk, and frog. There are actually 8 types of colloid mixtures, they are usally described by orginal state.

7 0

3 years ago

Which of the following objects have kinetic energy?

Montano1993 [528]

I think the Answer is A (An elephant walking 1.5 m/s along the ground), and B (A jet flying across the sky 4,000 m above the ground.

4 0

1 year ago

A bug is 12 cm from the center of a turntable that is rotating with a frequency of 45 rev/min . What minimum coefficient frictio

Agata [3.3K]

Answer:

The minimum coefficient of friction is 0.27.

Explanation:

To solve this problem, start with identifying the forces at play here. First, the bug staying on the rotating turntable will be subject to the centripetal force constantly acting toward the center of the turntable (in absence of which the bug would leave the turntable in a straight line). Second, there is the force of friction due to which the bug can stick to the table. The friction force acts as an intermediary to enable the centripetal acceleration to happen.

Centripetal force is written as

$F_c = m\frac{v^2}{r}$

with v the linear velocity and r the radius of the turntable. We are not given v, but we can write it as

$v = r\omega$

with ω denoting the angular velocity, which we are given. With that, the above becomes:

$F_c = m\frac{v^2}{r}=m\omega^2 r$

Now, the friction force must be at least as much (in magnitude) as Fc. The coefficient (static) of friction μ must be large enough. How large?

$F_r=\mu mg \geq m\omega^2 r = F_c\implies\\\mu \geq \frac{\omega^2 r}{g}$

Let's plug in the numbers. The angular velocity should be in radians per second. We are given rev/min, which can be easily transformed by a factor 2pi/60:

$\frac{1 rev}{1 min}\cdot\frac{\frac{2\pi rad}{rev}}{\frac{60s}{1 min}}=\frac{2\pi}{60}\frac{rad}{s}$

and so 45 rev/min = 4.71 rad/s.

$\mu \geq \frac{\omega^2 r}{g}=\frac{4.71^2\frac{1}{s^2}\cdot 0.12m}{9.8\frac{m}{s^2}}=0.27$

A static coefficient of friction of at least be 0.27 must be present for the bug to continue enjoying the ride on the turntable.

3 0

3 years ago