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Why must the height of the meniscus in the graduated cylinder match the height of the water in the tub when measuring volume?

galben [10]

Answer:

See explanation

Explanation:

First, in order for you to understand, remember the basic concept of meniscus in graduated cylinder.

"The meniscus is the curve seen at the top of a liquid in response to its container. The meniscus can be either concave or convex, depending on the surface tension of the liquid and its adhesion to the wall of the container".

Now, according to this definition, and for water, the reading of the volume must be donde at the bottom of the curve of the meniscus. This is because the water gives a concave curve.

If you read it and matches the height of water, you are getting two results:

One, get an accurate value or volume, because it's been done at eye level.

The second fact is that when you do the reading this way, The total pressure is made equal to the atmospheric pressure by adjusting the height of the cylinder until the water level is equal.

8 0

3 years ago

I need help with this question ASAP please :)

Nana76 [90]

Answer: 1.67 x 10-7 N

3 0

3 years ago

Please help. Which describe colloids? Check all that apply.

rewona [7]

A) heterogeneous mixture & I believe B?

I know A is correct though

3 0

3 years ago

The combination of an applied force and a friction force produces a constant total torque of 35.5 N · m on a wheel rotating abou

Cerrena [4.2K]

Answer:

a) $I = 19.799\,kg\cdot m^{2}$ , b) $T = -3.405\,N\cdot m$ , c) $n_{T} \approx 54.842\,rev$

Explanation:

a) The net torque is:

$T = I\cdot \alpha$

Let assume a constant angular acceleration, which is:

$\alpha = \frac{\omega-\omega_{o}}{t}$

$\alpha = \frac{10.4\,\frac{rad}{s} - 0\,\frac{rad}{s} }{5.80\,s}$

$\alpha = 1.793\,\frac{rad}{s^{2}}$

The moment of inertia of the wheel is:

$I = \frac{T}{\alpha}$

$I = \frac{35.5\,N\cdot m}{1.793\,\frac{rad}{s^{2}} }$

$I = 19.799\,kg\cdot m^{2}$

b) The deceleration of the wheel is due to the friction force. The deceleration is:

$\alpha = \frac{\omega-\omega_{o}}{t}$

$\alpha = \frac{0\,\frac{rad}{s} - 10.4\,\frac{rad}{s}}{60.4\,s}$

$\alpha = - 0.172\,\frac{rad}{s^{2}}$

The magnitude of the torque due to friction:

$T = (19.799\,kg\cdot m^{2})\cdot (-0.172\,\frac{rad}{s^{2}} )$

$T = -3.405\,N\cdot m$

c) The total angular displacement is:

$\theta_{T} = \theta_{1} + \theta_{2}$

$\theta_{T} = \frac{(10.4\,\frac{rad}{s} )^{2}-(0\,\frac{rad}{s} )^{2}}{2\cdot (1.793\,\frac{rad}{s^{2}} )} + \frac{(0\,\frac{rad}{s} )^{2}-(10.4\,\frac{rad}{s} )^{2}}{2\cdot (-0.172\,\frac{rad}{s^{2}} )}$

$\theta_{T} = 344.580\,rad$

The total number of revolutions of the wheel is:

$n_{T} = \frac{\theta_{T}}{2\pi}$

$n_{T} = \frac{344.580\,rad}{2\pi}$

$n_{T} \approx 54.842\,rev$

5 0

3 years ago

Mr. Roberts drives his car away from his house at a constant speed. Which of the following represents

zepelin [54]

Speed is represented by distance divided by time. Graphically, constant speed is represented by a horizontal line on a speed-time graph.

Explanation

In a very literal sense speed is considered to be scalar quantity and denotes how fast or quick objects move. Therefore, speed is considered to be the velocity or swiftness of an object to cover a certain amount of distance.
There three types of speed high speed, average speed, and zero speed. Any object which moves at very high speed or moves very fast and quickly and subsequently can cover the considerable distance is called high-speed object. On the other hand, the average speed of an object is defined as the total distance covered divided by the time taken to cover that distance. Again when the object doesn't cover any distance at a given time or any object which has got no movement in it is called zero speed object.
Constant speed objects are those objects which move at a constant speed. Constant speed here refers to mean objects which move at the same speed without increasing or decreasing.If we try to represent constant speed on the diagram or through graph it can be done by drawing a horizontal line on the speed-time- graph. Here Mr. Robert drives his car at a constant speed means that he was driving his car without increasing or decreasing the speed or at the same speed.It has the same increase in distance in the given time. Time increases at the right and distance increase constantly with time.

4 0

3 years ago