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Some amount of water is evaporated from a 2.0 L, 0.2 M NaI solution, to from a 1.0 L solution. The molar mass of NaI is 150 g/mo
1 answer:
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The right answer is C) 60 g/L
To know the final concentration of NaI solution, you'll need to calculate the initial amount of NaI in grams in the following way:
Next, you only need to calculate the concentration on NaI in the new 1 L solution, because only water is evaporating from the initial solution:
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The right answer is C) 60 g/L
To know the final concentration of NaI solution, you'll need to calculate the initial amount of NaI in grams in the following way:
Next, you only need to calculate the concentration on NaI in the new 1 L solution, because only water is evaporating from the initial solution:
Have a nice day!
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Answer:
T₂ = 43.46 °C
Explanation:
Given that:
The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)
It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J
Heat gain by water = Heat lost by the reaction
Thus,
For water:
Mass of water = 5100 g
Specific heat of water = 4.18 J/g°C
T₁ = 25 °C
T₂ = ?
Q = 393500 J
So,
T₂ = 43.46 °C