The Answer is here
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Answer:
1.6675×10^-16N
Explanation:
The force of gravity that the space shuttle experiences is expressed as;
g = GM/r²
G is the gravitational constant
M is the mass = 1.0 x 10^5 kg
r is the altitude = 200km = 200,000m
Substitute into the formula
g = 6.67×10^-11 × 1.0×10^5/(2×10^5)²
g = 6.67×10^-6/4×10^10
g = 1.6675×10^{-6-10}
g = 1.6675×10^-16N
Hence the force of gravity experienced by the shuttle is 1.6675×10^-16N
Answer:
Soory
Explanation:
I really dont know but i will send you wait
For finding the orbital speed of the satellite we can say that the centripetal force for the circular motion of satellite is provided by the gravitational force of earth
so here we can say


now we will have

now here we will say that orbital speed of the satellite is inversely depends on the orbital radius
<em>So here if orbital speed is half then as per above relation we can say that orbital distance will become four times</em>
<em>Also we can say that if orbital speed is double then orbital distance will become one fourth of initial distance.</em>