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Leto [7]
3 years ago
12

Molecules rearrange and form new molecules reversible

Physics
2 answers:
Mademuasel [1]3 years ago
7 0
1. exchange- Molecules rearrange and form new molecules <span>
2. </span>reversible- simultaneous decomposition and synthesis <span>
3. </span>decomposition- bonds broken and elements released <span>
4.</span> synthesis- molecules formed from components
STALIN [3.7K]3 years ago
6 0
1. <span>Molecules rearrange and form new molecules - exchange (they exchange some material in order to produce new things)
2. </span><span>simultaneous decomposition and synthesis - reversible (it can go back)
3. </span><span>bonds broken and elements released - decomposition
4. </span><span>molecules formed from components - synthesis (these components merge and create molecules)</span>
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6 0
3 years ago
A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The
Goshia [24]

Answer:

0.629\ \text{rad/s}^2 counterclockwise

9.98\ \text{s}

Explanation:

r_1 = Small drive wheel radius = 2.2 cm

\alpha_1 = Angular acceleration of the small drive wheel = 8\ \text{rad/s}^2

r_2 = Radius of pottery wheel = 28 cm

\alpha_2 = Angular acceleration of pottery wheel

As the linear acceleration of the system is conserved we have

r_1\alpha_1=r_2\alpha_2\\\Rightarrow \alpha_2=\dfrac{r_1\alpha_1}{r_2}\\\Rightarrow \alpha_2=\dfrac{2.2\times 8}{28}\\\Rightarrow \alpha_2=0.629\ \text{rad/s}^2

The angular acceleration of the pottery wheel is 0.629\ \text{rad/s}^2.

The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.

\omega_i = Initial angular velocity = 0

\omega_f = Final angular velocity = 60\ \text{rpm}\times \dfrac{2\pi}{60}=6.28\ \text{rad/s}

t = Time taken

From the kinematic equations of linear motion we have

\omega_f=\omega_i+\alpha_2t\\\Rightarrow t=\dfrac{\omega_f-\omega_i}{\alpha_2}\\\Rightarrow t=\dfrac{6.28-0}{0.629}\\\Rightarrow t=9.98\ \text{s}

The time it takes the pottery wheel to reach the required speed is 9.98\ \text{s}

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3 years ago
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