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Artemon [7]
2 years ago
6

When a man returns to his well-sealed house on a summer day, he finds that the house is at 35°C. He turns on the air conditioner

, which cools the entire house to 20°C in 38 min. If the COP of the air-conditioning system is 2.8, determine the power drawn by the air conditioner. Assume the entire mass within the house is equivalent to 800 kg of air for which cv = 0.72 kJ/kg·°C and cp = 1.0 kJ/kg·°C
Physics
2 answers:
Paul [167]2 years ago
6 0

Answer:

1353.38 Watt

Explanation:

T₁ = Initial temperature of the house = 35°C

T₂ = Final temperature of the house = 20°C

Δt = Time taken to cool the house = 38 min = 38×60 = 2280 s

m = mass of air in the house = 800 kg

Cv = Specific heat at constant volume = 0.72 kJ/kgK

Cp = Specific heat at constant pressure = 1.0 kJ/kgK

Heat removed

q = mCvΔT

⇒q = 800×720×(35-20)

⇒q = 8640000 J

Average rate of hear removal

Q=\frac{q}{\Delta t}\\\Rightarrow Q=\frac{8640000}{2280}\\\Rightarrow Q=3789.47\ W

COP=\frac{Q}{W}\\\Rightarrow W=\frac{Q}{COP}\\\Rightarrow W=\frac{3789.47}{2.8}\\\Rightarrow W=1353.38\ W

∴ Power drawn by the air conditioner is 1353.38 Watt

aev [14]2 years ago
4 0

Answer:

 W_in = 1.353 KW

Explanation:

Given:

- Initial temperature of the house T_1 = 35°C

- Final temperature of the house T_2 = 20°C

- Time taken to cool the house dt = 38 min = 38×60 = 2280 s

- mass of air in the house m = 800 kg

- Specific heat at constant volume c_v = 0.72 kJ/kgK

- Specific heat at constant pressure c_p = 1.0 kJ/kgK

Find:

- Determine the power drawn by the air conditioner.

Solution:

- We will first compute the rate of heat removal from the room, we will use c_v due to a constant volume process, as follows:

                                 Q_l = m*c_v*dT/dt

- In put values given:

                                 Q_l = 800*0.72*(35-20) / 2280

                                 Q_l = 3.7894 KW

- The relationship between the heat rejection and the COP of an air conditioner is given as:

                                 COP = Q_l / W_in

                                 W_in = Q_l / COP

                                 W_in = 3.7894 / 2.8

                                 W_in = 1.353 KW

- Hence the amount of power required for this process is 1.353 KW

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Total displacement of the car: 405 m

Explanation:

The first part of the motion of the car is a uniformly accelerated motion, so we can use the suvat equation

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Now we can find the distance covered by the car in the 2nd part, where it decelerates after having seen the tree limb on the road. We can do it by using the suvat equation:

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