Answer:
x = -2, y = -4, or (-2, -4).
Step-by-step explanation:
5x + y = -14
5x - 3y = 2
If we look at the first equation, we can see that y can be easily isolated.
5x + y = -14
Subtract 5x from both sides.
y = -5x - 14
Now we have a variable that we can plug into the second equation.
5x - 3y = 2
5x - 3(-5x - 14) = 2
Distribute the -3 across each term in the parentheses.
5x + 15x + 42 = 2
Combine like terms.
20x + 42 = 2
Subtract 42 from both sides.
20x = -40
Divide both sides by 20 to isolate x.
x = -2
Plug in x = -2 back into one of the equations to find y.
y = -5x - 14
y = -5(-2) - 14
Multiply.
y = 10 - 14
Subtract.
y = -4
Our solution is x = -2, y = -4, or (-2, -4).
Check your answer by plugging both values into one of the equations.
5x - 3y = 2
5(-2) - 3(-4) = 2
-10 + 12 = 2
2 = 2
Your answer is correct.
Hope this helps!
Answer:
When Jeff travels more than 20 miles
Step-by-step explanation:
Let 'x' be the number of miles traveled by Jeff.
In order for the national car company to be less expensive, then the following condition must be met:
![12+0.30x < 10+0.40x\\12-10 < 0.4x-0.3 x\\2](https://tex.z-dn.net/?f=12%2B0.30x%20%3C%2010%2B0.40x%5C%5C12-10%20%3C%200.4x-0.3%20x%5C%5C2%20%3C0.1x%5C%5C20%3Cx)
This means that when Jeff travels more than 20 miles, it is cheaper to rent from the national car company.
Answer:
The answer is AC = 3.76
Step-by-step explanation:
CohCahToa
Coh: sin(theta) = Opp/Hyp
sin(theta°) = AC/AB
sin(70°) = AC/4
AC = 4*sin(70°)
AC ≈ 3.758770483
AC = 3.76
Answer:
14r
Step-by-step explanation:
since there are 14 members and each sold r tickets r x 14 which is 14r
Answer:
See attachment
Step-by-step explanation:
We want to graph the following equation:
x-y+1=0
and
3x+2y=12
For the first equation: x-y+1=0
When x=0, we have 0-y+1=0---->y=1
We plot the point (0,1)
When y=0, we have x-0+1=0---->x=-1
We plot (-1,0)
We draw a straight line through these two points to get the graph of this line.
For the second equation: 3x+2y=12
When x=0,y=6. So we plot (0,6)
When y=0, x=4, So we plot (4,0)
We draw another straight line through them to obtain the graph in the attachment.