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beks73 [17]
3 years ago
8

PLEASE HELP The arrows in the chart below represent phase transitions.

Chemistry
1 answer:
Alona [7]3 years ago
5 0

1, 2, and 3

hope it helps next time upload with picture

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553.5 mL ?:cm^3<br> how do i get my answer? and what is the answer?
dmitriy555 [2]

Answer:

553.5 cm3

Reason:

1 mL = 1 cm3

6 0
3 years ago
Determine the mass in grams of each nacl solution that contains 1.5g of nacl
Rama09 [41]

Answer:- 3333 g of solution.

Some of the question part is missing here. It would be like, "Determine the mass in grams of each NaCl solution that contains 1.5 g of NaCl.

(i) 0.045% NaCl by mass

Solution:- 0.045% NaCl by mass means 0.045 g of NaCl are present in 100 g of solution. 1.5 g of NaCl would be present in how many grams of solution?

We could solve this using proportions...

(0.045/100) = (1.5/X)

0.045(X) = 1.5(100)

0.045X = 150

X = 150/0.045 = 3333

So, 1.5 g of NaCl is present in 3333 g of solution.

7 0
3 years ago
what is the molarity of a solution made by dissolving 21.2 g of sodium hydroxide in enough water to make 7.92 L of solution
VashaNatasha [74]

Answer:

0.067M NaOH is the answer

4 0
2 years ago
what carboxylic acid describes this? have a long chain of carbons with hydrogen attached to each one. The end carbon has a hydro
bekas [8.4K]
I think the answer would be fatty acids
5 0
3 years ago
In the laboratory, a general chemistry student measured the pH of a 0.486 M aqueous solution of triethanolamine, C6H15O3N to be
STatiana [176]

Answer:

Kb = 6.22x10⁻⁷

Explanation:

Triethanolamine, C₆H₁₅O₃N, is in equilibrium with water:

C₆H₁₅O₃N(aq) + H₂O(l) ⇄ C₆H₁₅O₃NH⁺(aq) + OH⁻(aq)

Kb is defined from concentrations in equilibrium, thus:

Kb = [C₆H₁₅O₃NH⁺] [OH⁻] / [C₆H₁₅O₃N]

The equilibrium concentration of these compounds could be written as:

[C₆H₁₅O₃N] = 0.486M - X

[C₆H₁₅O₃NH⁺] = X

[OH⁻] = X

pH is -log [H⁺], thus, [H⁺] = 10^-pH = 1.820x10⁻¹¹M

Also, Kw = [OH⁻] ₓ [H⁺];

1x10⁻¹⁴ = [OH⁻] ₓ [H⁺]

1x10⁻¹⁴ = [OH⁻] ₓ [1.820x10⁻¹¹M]

5.495x10⁻⁴M = [OH⁻], that means <em>X = 5.495x10⁻⁴M</em>

Replacing in Kb formula:

Kb = [5.495x10⁻⁴M] [5.495x10⁻⁴M] / [0.486M-5.495x10⁻⁴M]

<em>Kb = 6.22x10⁻⁷</em>

<em></em>

5 0
2 years ago
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