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3 years ago

PLEASE HELP The arrows in the chart below represent phase transitions.

Chemistry

1 answer:

Alona [7]3 years ago

5 0

1, 2, and 3

hope it helps next time upload with picture

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A sample of a radioactive isotope initially contains 20 x 10^10 atoms. After 16 days, 5 x 10^10 atoms remain. what is the half-l

nekit [7.7K]

I think the answer is A but I could be wrong

7 0

4 years ago

What is the answer for this please ?<br> HNO3 + OH →

BartSMP [9]

Answer:

HNO3(aq) + OH-(aq) → NO3-(aq) + H2O(l)

Explanation:

According to Bronsted-Lowry theory, an acid is a substance that donates a proton (H+) and produces a conjugate base while a base is a molecule or ion which accepts the proton.

An example of Bronsted-Lowry acid and base is Nitric acid, HNO3 and hydroxide ion, OH- respectively as shown in the given reaction.

Thus, the nitric acid acts as an acid by donating a proton to the hydroxide ion which accepts it, thus producing nitrate ion, NO3- as a conjugate base, while OH- produces H2O as a conjugate acid.

8 0

3 years ago

the length of a string is 16cm.Its length becomes 20cm when supporting a weight of 5N.Calculate the length of the string when su

guapka [62]

Answer:

Explanation:

According to hooks law "provide the elastic limit of an elastic material is not exceeded the extension e is directly proportional to the applied force F"

$F= ke$

where F= applied force

k= spring constant

e= extension

Given data

length of string l = 16cm

extension e = 20-16= 4cm

applied force = 5N

we need t o first calculate the spring constant k

apply the formula

$F= ke$

$5=k*4\\k= \frac{5}{4} \\k= 1.25N/cm$

we can now calculate the extension of the string when supporting a 6N weight

$F= ke\\6=1.25*e\\e= \frac{6}{1.25} \\e= 4.8cm$

The length of the string when supporting a 6N weight is

$= length+ extension\\= 16+4.8\\= 20.8cm$

<em>COMMENT </em><em>:According to the analysis an extra weight of 1N will cause add 0.8cm to the length of the string</em>

4 0

3 years ago

3. Potassium chlorate, KC103, decomposes when heated to produce potassium

FromTheMoon [43]

Answer: oxygen=2.547g

Explanation:

Based on the question,it was observed that the reaction is reversible

2 moles of KClO3 gives 2 moles of KCl and three moles of O2

Molar mass for KClO3 is 245 g/mol

Molar mass for O2 is 96 g/mol

We are to find the mass of O2 and we Are given the mass KCLO3 is 6.50g

245g of KClO3 gives 96g of O2

6.50g of KClO3 gives xg of O2

Cross multiply

245x=624

X=624/245

X=2.547g

Therefore the gram of oxygen is 2.547g

5 0

3 years ago

Give the structure of the expected organic product in the reaction of 3-phenylpropanal with each of the following:

Misha Larkins [42]

Answer:

Please see attachment

Explanation:

Please see attachment

6 0

4 years ago