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inn [45]
4 years ago
13

A current of 0.5A flows in a circuit. Determine the quantity of charge that crosses a point in 4 minutes

Physics
1 answer:
zhannawk [14.2K]4 years ago
5 0

0.5 A means 0.5 Coulomb of charge every second.

4 minutes = 240 seconds

(0.5 C/sec) x (240 sec)= 120 Coulombs

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An Olympic-class sprinter starts a race with an acceleration of 5.10 m/s2. What is her speed 2.40 s later?
ivolga24 [154]

Answer:

12.24 m/s

Explanation:

Speed: This can be defined as the rate of change of distance with time. The S.I unit of speed is m/s.

Using the formula,

a = v/t................ Equation 1

Where a = acceleration of the sprinter, v = speed of the sprinter, t = time.

making v the subject of the equation,

v = at ................. Equation 2

Given: a = 5.1 m/s², t = 2.4 s.

Substitute into equation 2

v = 5.1(2.4)

v = 12.24 m/s.

Hence, the speed of the sprinter = 12.24 m/s

3 0
4 years ago
What would an automobile engineer MOST LIKELY suggest to improve the efficiency of a car's engine? A) Remove the engine's coolin
TiliK225 [7]

Answer:

D) Reduce the internal friction of the engine's parts.

Explanation:

To increase the efficiency of the car's engine, an engineer most like has to reduce the friction within the internal engine parts. Reducing these friction reduces the useful energy lost as heat in these internal parts of the engine, when the engine parts do work against friction to move. In most everyday activities, engines and machines, energy is usually lost as heat due to frictional forces arising from two or more surfaces in contact.

3 0
4 years ago
How far must you be from a 110 W speaker to have an intensity of 0.0439 W/m^2? (Treat the speaker as a point source.)
Lina20 [59]

Answer:

d=14.12m

Explanation:

Assume a point sound source that emits a sound power<em> P </em>(in W) evenly in all directions of space. Let us also assume that the medium does not absorb this sound power when it passes through it. At a distance<em> d </em>from the source this power will have been evenly distributed over the surface of a sphere of radius <em>d</em>. Therefore, the acoustic intensity I at distance d will be worth:

I=\frac{P}{4\pi d^{2}}

This is the expression of the so-called<em> law of the square of distance: "the intensity is inversely proportional to the square of the distance to the source (considered punctual)".</em>

So

I=0.0439 \frac{W}{ m^{2}}

P=110W

d=\sqrt { \frac{P}{4 \pi\\I}

d=\sqrt{ \frac{110}{ 4\pi (0,0439)} }

d=\sqrt{{199.39}

d=14.12m

3 0
3 years ago
A 4.3-kg block slides down an inclined plane that makes an angle of 30° with the horizontal. Starting from rest, the block slide
-BARSIC- [3]

Answer:

0.56

Explanation:

Let the coefficient of friction is μ.

m = 4.3 kg, θ = 30 degree, initial velocity, u = 0, s = 2.7 m, t = 5.8 s

By the free body diagram,

Normal reaction, N = mg Cosθ = 4.3 x 9.8 x Cos 30 = 36.49 N

Friction force, f = μ N = 36.49 μ

Net force acting on the block,

Fnet = mg Sinθ - f = 4.3 x 9.8 x Sin 30 - 36.49 μ

Fnet = 21.07 - 36.49μ

Net acceleartion, a = Fnet / m

a = (21.07 - 36.49μ) / 4.3

use second equation of motion

s = ut + 1/2 a t^2

2.7 = 0 + 1/2 x (21.07 - 36.49μ) x 5.8 x 5.8 / 4.3

By solving we get

μ = 0.56

8 0
4 years ago
The sphere that refers to Earth's water is called what?
WARRIOR [948]

Answer:

Its called the hydrosphere UwU!

Explanation:

6 0
3 years ago
Read 2 more answers
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