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adelina 88 [10]
3 years ago
14

A 150 kg bike takes a roundabout with a radius of 53.0 m. The roundabout it’s only ¾ of a circle. the time taken was 0.35 minute

s. Determine the acceleration and the net force acting upon the bike.
Physics
1 answer:
BigorU [14]3 years ago
5 0

Answer:

ef<grhtxdgfkugılohşrgzfxthyjhuk

Explanation:dfbgdhzfgbfxgzbfxd

fadwgfrsdfkyugılhşojipdaftshrthsxxfbzxryfchtgghxfjnx hjnnvbm bn dfkunggvxbvbbfbfxxb

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Which of the below statements are true?
andrezito [222]

Answer:

B

Explanation:

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if you start at point A, then go to point B, and back to point A, the displacement is zero because you started and ended at the same point.

for this question, pretend you started at point A, went east 20 km to point B, and then west 8 km to point C, your displacement is 12 km. 12 km is the distance between point A and point C.

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I believe your answer is correct, because 8.7*10^-7 is equal to 0.00000085347.

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1. On this graph, what is the change in velocity between 5 seconds and 8 seconds?
alukav5142 [94]
Can I see the graph so I can help you
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Which of the following statements is accurate? A. Sound waves passing through the air will do so as transverse waves, which vibr
egoroff_w [7]

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7 0
3 years ago
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Sharks and related fish can sense the extremely weak electric fields emitted by their prey in the surrounding waters. These dete
Sonja [21]

Answer

2) 1.5×10-2 m

Explanation

The potential difference is related to the electric field by:

\Delta V=Ed (1)

where

\Delta V is the potential difference

E is the electric field

d is the distance

We want to know the distance the detectors have to be placed in order to achieve an electric field of

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\Delta V=1.5 V

Solving the equation (1) for d, we find

d=\frac{\Delta V}{E}=\frac{1.5 V}{100 V/m}=0.015 m=1.5 \cdot 10^{-2} m

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3 years ago
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