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adelina 88 [10]
3 years ago
14

A 150 kg bike takes a roundabout with a radius of 53.0 m. The roundabout it’s only ¾ of a circle. the time taken was 0.35 minute

s. Determine the acceleration and the net force acting upon the bike.
Physics
1 answer:
BigorU [14]3 years ago
5 0

Answer:

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Explanation:dfbgdhzfgbfxgzbfxd

fadwgfrsdfkyugılhşojipdaftshrthsxxfbzxryfchtgghxfjnx hjnnvbm bn dfkunggvxbvbbfbfxxb

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A robin in flight has 20.8 J of PE when it is 27.6 m high. What is the mass of the robin? (Unit = kg)
schepotkina [342]

Answer:

<h2>\boxed{  \bold{ \purple{0.0769 \: kg \: }}}</h2>

Explanation:

\sf{Potential   Energy ( P.E ) \:  =  \: 20.8 \: joule}

\sf{distance \:  = 27.6 \: metre}

\sf{mass = } ?

\sf{acceleration \: due \: to \: gravity = 9.68 \:  {metre \: per \: second}^{2} }

Now, let's find the mass:

\sf{PE  \:  =  mass \times gravity \:  \times  \: distance}

plug the values

⇒\sf{20.8 = m \times 9.8 \times 27.6}

Multiply the numbers

⇒\sf{20.8 = 270.48 \: m}

Swap the sides of the equation

⇒\sf{270.48m = 20.8}

Divide both sides of the equation by 270.48

⇒\sf{ \frac{270.48m}{270.48}  =  \frac{20.8}{270.48} }

Calculate

⇒\sf{0.0769} kg

Hope I helped!

Best regards!!

7 0
3 years ago
Read 2 more answers
Gauss's law is usualy written as :
snow_tiger [21]

Answer:

(a) the net charge inside the closed surface.

Explanation:

In Gauss' Law, Qencl refers to the net charge inside the Gaussian surface. This surface is usually taken as a symmetric geometric surface, but this is merely for simplicity. Gauss' Law holds for any closed surface. Inside this surface there can be insulators as well as conductors. Regardless of the geometry or the materials inside, Qencl refers to the net charge inside the closed surface. The charge outside the surface is irrelevant for Gauss' Law, therefore all the charge in the physical system is not included in Gauss' Law.

4 0
3 years ago
If displacement covered by a particle is zero then distance cover by it<br>​
sleet_krkn [62]

Answer:

When displacement is zero, the particle may be at rest, therefore, distance travelled = 0.

Again, when displacement is zero, the final position matches with the initial position after some time, but the distance travelled will not be zero.

7 0
2 years ago
In a tug of war, when one team is pulling with a force of 85 N and the other 40 N, what is the net
olya-2409 [2.1K]
85 N - 40 N = 45 N
And depending on direction the greater force is being pulled towards
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3 years ago
Technician A says that the intake and exhaust manifolds have to be removed before removing the engine from the vehicle. Technici
Amiraneli [1.4K]

Answer: Technician A is correct

Explanation:

The intake manifold is the compactment that all fuel and air supply to the cylinders. It's connected to the engine so it has to be disconnected while the exhaust manifold receives all the exhaust gases from the cylinders and releases the gas through a single or double exhaust gases outlet.

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