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katrin2010 [14]
3 years ago
15

A helicopter and a jet airplane must work against gravity in order to fly. Which one flys faster

Physics
1 answer:
Gre4nikov [31]3 years ago
3 0
Im pretty sure the jet airplane is faster
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A girl moves quickly to the center of a spinning merry-go-round, traveling along the radius of the merry-go-round. Which of the
DochEvi [55]

Answer:

The angular speed of the system increases.

The moment of inertia of the system decreases.

Explanation:

As we know that the girl is going towards the center of the circle so here the moment of inertia of the girl is given as

I = mr^2

here we know that

r = position of the girl from the center of the disc

now we know that the girl is moving towards the center so its distance will continuously decreasing

So the moment of inertia of the girl will decrease

Now we know that that with respect to the center of the disc there is no torque on the disc + girl system

So here we can use angular momentum conservation

So we have

I\omega = constant

since moment of inertia is decreasing for the system

so angular speed will increase

3 0
4 years ago
Please help! Will give thanks and branliest!!!!
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3 years ago
(3mrks) physics solar panel question
shtirl [24]
Some benefits to solar power:
Isolated power is very abundant on earth.
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Eco friendly excluding panel production.
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6 0
3 years ago
A unit mass of an ideal gas at temperature T undergoes a reversible isothermal process from pressure P1 to pressure P2 while los
mafiozo [28]

Answer:

Option B

Change in entropy of the process is \Delta S= Rln(\frac{P_{1}}{P_{2}})

Explanation:

The entropy of a system is a measure of the degree of disorderliness of the system.

The entropy of a system moving from process 1 to 2 is given as

\Delta S = \int\limits^2_1 {\frac{\delta q}{T}}

recall from first law, \delta q =du +Pdv

hence we have, \Delta S = \int\limits^2_1 {\frac{du +Pdv}{T}}

since the process is isothermal, du= 0

this gives us \Delta S = \int\limits^2_1 {\frac{Pdv}{T}}

integrating within the limits of 1 and 2, will give us

\Delta S = R ln (\frac{V_{2}}{V_{1}})

also from ideal gas laws,

\frac{V_{2}}{V_{1}}=\frac{P_{1}}{P_{2}}

hence we have    \Delta S = R ln (\frac{P_{1}}{P_{2}})

This makes the correct option B

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3 years ago
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