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denis-greek [22]
4 years ago
6

Conservation of momentum

Physics
1 answer:
hammer [34]4 years ago
5 0

That's a good one, and there's more to this than meets the eye.

Mass and velocity don't have to be conserved, but energy and
momentum both do !


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what occurs in a chemical reaction? A. Reactants are formed without chemical bonds being broken B. Reactants are formed from pro
Ann [662]
The answer is D. Products are formed from reactants by the breaking and forming of new bonds. 
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3 years ago
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In situation A, a bar magnet moves toward a stationary coil at a constant speed, and the maximum current is recorded. If the mag
slava [35]

The reversing of the magnet polarity will explain the different current reading.

Answer: Option D

<u>Explanation:</u>

According to Faraday's law of inductance, whenever a bar magnet is moved toward a stationary coil at constant speed, current will be generated in that coil. So in this case, the first maximum current in the above situation say A is recorded successfully.

Similarly, when the arrangement is kept as it is, in situation B, the current is observed to have different reading. This may be because of the polarity of the magnet would have changed leading to different current reading.

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3 years ago
A man holding a rock sits on a sled that is sliding across a frozen lake (negligible friction) with a speed of 0.460 m/s. The to
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Answer:

= 0.417 m/s

Explanation:

Momentum before throwing the rock: m*V = 95.0 kg * 0.460 m/s

= 44.27 N*s  

A) man throws the rock forward

mass of rock m1 = 0.310 kg

V1 = 15.5 m/s, in the same direction of the sled with the man

sled and man:

m2 = 95 kg - 0.310 kg = 94.69 kg

v2 = ?

Conservation of momentum:

momentum before throw = momentum after throw

44.27N*s = 0.310kg * 15.5m/s + 94.69kg*v2

⇒ v2 = [44.27 N*s - 0.310 * 15.5N*s ] / 94.69 kg

= 0.417 m/s

6 0
4 years ago
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A parachutist of mass 20.1 kg jumps out of an airplane at a height of 662 m and lands on the ground with a speed of 7.12 m/s. Th
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Answer:

1.30\cdot 10^5 J

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The energy lost due to air friction is equal to the mechanical energy lost by the parachutist during the fall.

The initial mechanical energy of the parachutist (at the top) is equal to his gravitational potential energy:

E_i=mgh

where

m = 20.1 kg is his mass

g=9.8 m/s^2 is the acceleration due to gravity

h = 662 m is the initial heigth

The final mechanical energy (at the bottom) is equal to his kinetic energy:

E_f=\frac{1}{2}mv^2

where

v = 7.12 m/s is the final speed of the parachutist

Therefore, the energy lost due to air friction is:

\Delta E=E_i-E_f=mgh-\frac{1}{2}mv^2=(20.1)(9.8)(662)-\frac{1}{2}(20.1)(7.12)^2=1.30\cdot 10^5 J

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4 years ago
A force of 73.8 newtons is applied to travel bag at an angle 39.0° with the horizontal. What are the horizontal and vertical com
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The horizontal component of the force is the product of the cosine of the angle and the magnitude of the force, Fx = (73.8 N)(cos 39) = 57.35 N. The vertical component of this force is the product of the sine of the angle and the force, Fy = (73.8 N)(sin 39) = 46.44 N.
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