<span>
</span><span>Waves on a pond are an example of which kind of wave?
</span>B. surface waves
Answer:
The new speed is 56.25 miles/hour.
Explanation:
Since speed = distance/time;
time = distance/speed.
While driving at 50 miles/hour, time taken for one to complete 1 mile is (1/50) hour
(1/50) hour = (1/50) × 3600s = 72 seconds.
So, if this time to complete 1 mile (72 seconds) is reduced by 8 seconds,
New time to complete 1 mile will be = 72 - 8 = 64 seconds = (64/3600) hour = 0.0178 hour
New speed would be = (1 mile/64 seconds) = (1 mile/0.0178 hour) = 56.25 miles/hour.
Hope this Helps!!!
Answer:
Approximately 
.
Explanation:
Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.
Look up the Rydberg constant for hydrogen: 
.
Look up the speed of light in vacuum: 
.
Look up Planck's constant: 
.
Apply the Rydberg formula to find the wavelength 
(in vacuum) of the photon in question:
.
The frequency of that photon would be:
.
Combine this expression with the Rydberg formula to find the frequency of this photon:
.
Apply the Einstein-Planck equation to find the energy of this photon:
.
(Rounded to three significant figures.)
We're told that the planets have EQUAL MASS.
If that's true, then the strength of the gravitational forces between
each planet and the star depends only on the distance between
them ... the farther a planet is from the star, the smaller the
gravitational forces are IF we're talking about planets with
equal masses.
Planet-X is closer to the star, and Planet-Y is farther from it.
From this we know that the gravitational forces between the
star and Planet-X are greater, and the forces between the star
and Planet-Y are smaller.
'A' says this.
'B' is totally absurd, because it talks about gravity repelling things.
'C' says exactly the opposite for the two planets.
'D' says that distance doesn't matter. We know this is absurd,
simply because we're never pulled toward Jupiter in our daily life.
Answer:
No
Explanation:
Please let me know if my answer is correct
