Object Falling from Rest. As an object falls from rest, its gravitational potential energy is converted to kinetic energy. Conservation of energy as a tool permits the calculation of the velocity just before it hits the surface. K.E. = J, which is of course equal to its initial potential energy.
Answer:
3.085 [m].
Explanation:
1) The rule:
m₁*g*l₁=m₂*g*l₂, where m₁ and l₁ - the mass and distance for the small child, m₂ and l₂ - for the big child;
2) according to the condigion l₁+l₂=5, then
3) it is possible to make up the system:
4) finally, l₁=145/47≈3.085 [m].
Answer:
P = 2.18 atm
Explanation:
The strategy here here is to use the ideal gas law
PV = nRT
since we know the temperature, volume and the n, the number of moles is mass/MW, and R is the gas constant 0.08205 LatmK⁻¹mol⁻¹:
MW HI = 127.91 gmol⁻¹
P = ( mass / MW ) x R x T / V
P= (50.0 g / 127.91 gmol⁻¹ ) x 0.08205 LatmK⁻¹mol⁻¹ x 340 K/ 5.00 L
P = 2.18 atm
( rounded to three significant figures which is the number of significant figures for temperature, mass and volume )
The correct option is (A) 2.5 m/s
Explanation:
Since,
v = fλ ---- (1)
where v = speed of the wave
f = frequency of the wave = 5 Hz
λ = wavelength of the wave = 0.5
Plug in the value in (1):
(1) => v = 5 * 0.5
v = 2.5 m/s
