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dusya [7]
3 years ago
14

Windmills are used to convert wind energy into a more useful form. In most cases, there are three

Physics
1 answer:
sdas [7]3 years ago
4 0
The kinetic energy of the wind ==> causes ==>
       the windmill to turn (mechanical energy) ==>
       which is used to turn an electric generator ==>
                      which generates electrical energy.
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A mechanic uses a jack to lift up a car. He exerts a force of 11,000 N at a distance of 3m from the axis of rotation. How much t
pshichka [43]

Answer:

<h2>The amount of torque put on the car is 33,000Nm</h2>

Explanation:

Formula for calculating torque is expressed as T = rFsin\theta\\ where;

r is the radius of the  of the arm of the jack = 3m

F is the force exerted = 11000

\theta\\ is the angle of rotation = 90°

On substituting;

T = 3*11000sin90^{o} \\T = 3*11000 (sin90^{o} =1)\\T = 33000Nm

6 0
3 years ago
List the 4 things technology can be.
inessss [21]

Technology can be the four things listed below...

  • Phones
  • Computers
  • TVs
  • Playstation or Xbox
6 0
3 years ago
Read 2 more answers
Numbers in exponential form
kaheart [24]
Do the same thing you were doing
5 0
3 years ago
Please help with both questions I’m giving all my points :) it’s 23 and 24
labwork [276]
Sorry just need points
8 0
3 years ago
Derek and Diane race each other on bicycles. Derek starts 4 seconds before Diane. He goes at a steady speed of 6 m/s. Diane star
ser-zykov [4K]

a. x(t) = vt' = v(t+4) = 6(t+4) [m]

Let's call:

t the time calculated from the moment Diane starts her motion and t' the time calculated from the moment Derek starts his motion. Derek starts his motion 4 seconds before Diane: this means that has an "advantage" of 4 seconds, so we can write

t'=t+4

Then:

v=6 m/s is the uniform speed of Derek

Derek is moving in a uniform motion, so Derek's position will be given by (assuming that the starting position is zero):

x(t) = vt' = v(t+4) = 6(t+4) [m]

We see that this is correct: in fact, when t=0 (instant when Diane starts her motion), Derek has already travelled for

x(t=0)=v(0+4)=6 (4)=24 m


b. x'(t)= \frac{1}{2}at^2 =\frac{1}{2}(2)t^2=t^2 [m]

t is the time calculated from the moment Diane starts her motion. Diane is moving by accelerated motion, with constant acceleration a=2 m/s^2 and initial velocity v_0=0, so its position at time t is given by the law of uniform accelerated motion:

x'(t)= \frac{1}{2}at^2 =\frac{1}{2}(2)t^2=t^2


c. t = 8.74 s

The time t at which Diane catches up with Derek is the time t at which the positions of the two persons is equal:

x(t)=x'(t)

By solving, we have:

6 (t+4) = t^2\\t^2 -6t -24 =0

Which has two solutions:

t = -2.74 s --> negative, we can discarde it

t = 8.74 s --> this is our solution


d. 76.4 m

When Diane catches Derek, at t=8.74 s, she has covered the following distance:

x'(t=8.74s)=t^2 = (8.74 s)^2=76.4 m

We can verify that Derek is at the same position:

x(t=8.74 s)=6(t+4)=6(8.74 +4)=76.4 m

8 0
3 years ago
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