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Step2247 [10]
3 years ago
14

A certain shade of blue has a frequency of 7.07 × 1014 Hz. What is the energy of exactly one photon of this light?

Chemistry
2 answers:
taurus [48]3 years ago
8 0

Answer:

E=4.68\times 10^{-19}\ J

Explanation:

It is given that,

Frequency of shade of blue, f=7.07\times 10^{14}\ Hz

Let E is the energy of exactly one photon of this light. The relationship between the energy and the frequency is given by :

E=h\times f

h is the Planck's constant

E=6.63\times 10^{-34}\times 7.07\times 10^{14}

E=4.68\times 10^{-19}\ J

So, the energy of exactly one photon of this light is 4.68\times 10^{-19}\ J. Hence, this is the required solution.

IRISSAK [1]3 years ago
4 0
E = HF, where H is Planck's constant, 6.63 x 10 -  34 j.s
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