Question

A certain shade of blue has a frequency of 7.07 × 1014 Hz. What is the energy of exactly one photon of this light?

Answer 1

Answer:

$E=4.68\times 10^{-19}\ J$

Explanation:

It is given that,

Frequency of shade of blue, $f=7.07\times 10^{14}\ Hz$

Let E is the energy of exactly one photon of this light. The relationship between the energy and the frequency is given by :

$E=h\times f$

h is the Planck's constant

$E=6.63\times 10^{-34}\times 7.07\times 10^{14}$

$E=4.68\times 10^{-19}\ J$

So, the energy of exactly one photon of this light is $4.68\times 10^{-19}\ J$. Hence, this is the required solution.

Answer 2

E = HF, where H is Planck's constant, 6.63 x 10 -  34 j.s