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vichka [17]
3 years ago
4

Fill in the blanks with vocabulary terms.All vocab terms should be in lower case.

Chemistry
1 answer:
zepelin [54]3 years ago
3 0

Answer :

<u>Oxidation </u>is the loss of electrons.

<u>Reduction </u>is the gain of electrons.

The compound that became reduced acts as the <u>oxidizing </u>agent.

The compound that became oxidized acts as the <u>reducing </u>agent.

The measure of a compounds likeliness to gain or lose an electron is its <u>electrochemical potential</u> (E value).

A common electron carrier we will use a lot in this class is <u>NAD⁺</u> when it is in the oxidized state and <u>NADH </u>when it is in the reduced state.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced.

Electrochemical potential : It is defined as the measurement of the potential difference between two half cells.

Electron carrier : The molecules that are capable of accepting 1 or 2 electrons from one molecule and donating to another molecule in the process of electron transport.

There are two important electron carriers:

Nicotinamide adenine dinucleotide (NAD⁺ in its oxidized form and NADH in its reduced form).

Flavin adenine dinucleotide (FAD)

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olga55 [171]

Answer: (a) K *[A][B]^2

(b) The answer is B

Explanation:

A)

Step1:A+B<--> C (fast)

Step2: B+C→D(slow)

Rate depends on slowest step.

so,

rate = k' [B][C] ...eqn 1

But C is intermediate.so use step 1

Since 1st step is an equilibrium,

Kc = [C] /[A][B]

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rate = k' *[B] * Kc [A][B]

= k'Kc*[A][B]^2

= K *[A][B]^2 {writing k'Kc = K}

Answer: K *[A][B]^2

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Answer is B

Since rate depends on slowest step.

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For the reaction Fe3O4(s) + 4H2(g) --&gt; 3Fe(s) + 4H2O(g)
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Answer : The value of equilibrium constant for this reaction at 328.0 K is 1.70\times 10^{15}

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As we know that,

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\Delta S^o = standard entropy = 169.4 J/K

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Now put all the given values in the above formula, we get:

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The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln k

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\Delta G^o = standard Gibbs free energy  = 95636.8 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 328.0 K

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Now put all the given values in the above formula, we get:

95636.8J=-(8.314J/K.mol)\times (328.0K)\times \ln k

k=1.70\times 10^{15}

Therefore, the value of equilibrium constant for this reaction at 328.0 K is 1.70\times 10^{15}

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