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3 years ago

Fill in the blanks with vocabulary terms.All vocab terms should be in lower case.

Chemistry

1 answer:

zepelin [54]3 years ago

3 0

Answer :

Oxidation is the loss of electrons.

Reduction is the gain of electrons.

The compound that became reduced acts as the oxidizing agent.

The compound that became oxidized acts as the reducing agent.

The measure of a compounds likeliness to gain or lose an electron is its electrochemical potential (E value).

A common electron carrier we will use a lot in this class is NAD⁺ when it is in the oxidized state and NADH when it is in the reduced state.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced.

Electrochemical potential : It is defined as the measurement of the potential difference between two half cells.

Electron carrier : The molecules that are capable of accepting 1 or 2 electrons from one molecule and donating to another molecule in the process of electron transport.

There are two important electron carriers:

Nicotinamide adenine dinucleotide (NAD⁺ in its oxidized form and NADH in its reduced form).

Flavin adenine dinucleotide (FAD)

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A 5.76 liter sample of a gas at 22.00C mL 748 torr pressure was heated to a final volume of 17.28 liters, with the pressure rema

timama [110]

Answer:

The final temperature was 612 °C

Explanation:

Charles's law relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, using a constant of direct proportionality. In this law, Charles says that at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

$\frac{V}{T}=k$

When you want to study two different states, an initial and a final one of a gas and evaluate the change in volume as a function of temperature or vice versa, you can use the expression:

$\frac{V1}{T1} =\frac{V2}{T2}$

In this case:

V1= 5.76 L
T1= 22 °C= 295 °K (Being 0°C=273°K)
V2=17.28 L
T2=?

Replacing:

$\frac{5.76 L}{295 K} =\frac{17.28 L}{T2}$

Solving:

$T2 =\frac{17.28 L}{\frac{5.76 L}{295 K}}=\frac{17.28 L*295 K}{5.76 L}$

T2= 885 °K = 612 °C

The final temperature was 612 °C

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3 years ago

2.24g of iron combine with 0.96g of oxygen to form an oxide of iron. Determine the formula of this oxide of iron and use it to c

irakobra [83]

Answer:

See Explanation

Explanation:

Let us find the number of moles of each element

For iron = 2.24g/56 = 0.04 moles

For oxygen = 0.96 g/16 = 0.06 moles

Then we divide by the lowest ratio;

0.04/0.04 and 0.06/0.04

1 and 2

We Thus obtain 1 : 1.5

Multiplying through by 2 we have; 2 : 3

The formula of the oxide formed is Fe2O3

The balanced equation is;

4Fe + 3O2 ------> 2Fe2O3

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3 years ago

For an atom’s electrons, how many energy sublevels are present in the principal energy level n = 4?

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"n" represents principal energy level or principal quantum number. Principal energy levels are then subdivided into sublevels. The level of principal energy level is always equal to number of sublevels. Therefore if principal energy level = 4, then there are also 4 sublevels present, namely: 4s, 4p, 4d and 4f sublevels.

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3 years ago

If the mole fraction of sulfuric acid H2SO4 is 0.432 what is the percent by mass of H2SO4.

Sever21 [200]

Answer:

19.47%

Explanation:

The percentage by mass of $H_2SO_4$ would be 19.47%.

The percentage by mass of a substance in solution is calculated as:

$\frac{mass of substance}{mass of substance + water} * 100%$

Given that the mole fraction of $H_2SO_4$ = 0.432

The total number of mole fraction of a solution = 1

Hence, mole fraction of water = 1 - 0.432 = 0.568

Mass of water = molar mass x mole

= 98.079 x 0.432 = 42.37 g

Mass of $H_2SO_4$ = molar mass x mole

= 18.02 x 0.568 = 10.24 g

Hence,

%mass of $H_2SO_4$ = $\frac{10.24}{10.24 + 42.37} * 100$

= 19.47%

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3 years ago

What observed rotation is expected when a 1.72 M solution of (R)-2-butanol is mixed with an equal volume of a 0.860 M solution o

Allushta [10]

Answer:

α = -0,885°

Explanation:

The specific rotation [α] is defined as:

[α] = α/ c×l (1)

Where α is the observed rotation, c is concentration in g/mL, and l is optical path length in dm.

A racemic mixture has no optical activity. As the solution of (R)-2-butanol is mixed with an equal volume of the racemic mixture the concentration of the original solution decreases twice. That is 1,72M/2 = 0,86M. This concentration in g/mL is:

0,86mol/L× $\frac{1L}{1000mL}$ × $\frac{74,122g}{1mol}$ = 0,0637 g/mL

Replacing in (1):

$-13,9mL.g^{-1}.dm^{-1}=\frac{a}{0,0637g/mL*1dm}$

α = -0,885°

I hope it helps!

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3 years ago