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Juliette [100K]
2 years ago
7

8. How many atoms of cobalt are in a 0.39 mole sample of CoC

Chemistry
1 answer:
Debora [2.8K]2 years ago
3 0

8.98

×

N

A

 

cobalt atoms

Explanation:

N

A

,

Avogadro's number

specifies  

6.0221

×

10

23

individual particles. It is simply another collective number like a dozen, or a score, or a gross.  

N

A

has the property that  

6.0221

×

10

23

individual cobalt atoms has a mass of  

58.93

⋅

g

. How did I know that? Did I have it memorized?

So the quantity is  

≈

 

54

×

10

23

cobalt atoms.

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In one sample of a compound of copper and oxygen, 3.12g of the compound contains 2.50g of copper and the remainder is oxygen. Ca
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Answer:

% composition O = 19.9%

% composition Cu = 80.1%

Explanation:

Given data:

Total mass of compound = 3.12 g

Mass of copper = 2.50 g

Mass of oxygen = 3.12 - 2.50 = 0.62 g

% composition = ?

Solution:

Formula:

<em>% composition = ( mass of element/ total mass)×100</em>

% composition Cu = (2.50 g / 3.12 g)×100

% composition Cu = 0.80 ×100

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<em>% composition = ( mass of element/ total mass)×100</em>

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Read 2 more answers
How many liters is 1.9 mol of Cl2 at STP?
Lena [83]

Answer:

V = 42.6 L

Explanation:

Given data:

Number of moles of Cl₂ = 1.9 mol

Temperature and pressure = standard

Volume occupy = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

1 atm ×  V = 1.9 mol ×0.0821 atm.L /mol.K × 273.15 k

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8 0
2 years ago
A chemist fills a reaction vessel with mercurous chloride solid, mercury (I) aqueous solution, and chloride aqueous solution at
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Answer:

ΔG° = -533.64 kJ

Explanation:

Let's consider the following reaction.

Hg₂Cl₂(s) ⇄ Hg₂²⁺(aq) + 2 Cl⁻(aq)

The standard Gibbs free energy (ΔG°) can be calculated using the following expression:

ΔG° = ∑np × ΔG°f(products) - ∑nr × ΔG°f(reactants)

where,

ni are the moles of reactants and products

ΔG°f(i) are the standard Gibbs free energies of formation of reactants and products

ΔG° = 1 mol × ΔG°f(Hg₂²⁺) + 2 mol × ΔG°f(Cl⁻) - 1 mol × ΔG°f(Hg₂Cl₂)

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3 years ago
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