In this graph, what is the displacement of the particle in the last two seconds?of the particle in the last two seconds?
<span>0.2 meters
2 meters
4 meters
6 meters</span>
In this graph, the displacement of the particle in the last two seconds is 2 meters.
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Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:

where r = radius of orbit of Hubble Space Telescope
G = gravitational constant = 
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r = 
M = 
Therefore, T will be:


The orbital period of the Hubble Space Telescope is 5069.04 seconds.
Hi there!
We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.

There is NO initial vertical velocity, so:

Rearrange to solve for time:

Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)

Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:
