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3 years ago

9

Theresa is swinging a 4.0 kg ball on a 1.2 m long rope with a tangential speed of 1.8 m/s. What is the centripetal force exerted

on the rope? Round to the tenths place.

2 answers:

Ksju [112]3 years ago

8 0

You need to round and the answer is 10.8N

Vadim26 [7]3 years ago

5 0

For this case the centripetal force is given by:

$F = m * (\frac{v^2}{r})$

Where,

m: mass of the object

v: tangential speed

r: rope radius

Substituting values in the equation we have:

$F = (4.0) * (\frac{1.8^2}{1.2})$

Then, doing the corresponding calculations:

$F = 10.8 N$

Answer:

The centripetal force exerted on the rope is:

$F = 10.8 N$

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