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Rama09 [41]
3 years ago
9

Theresa is swinging a 4.0 kg ball on a 1.2 m long rope with a tangential speed of 1.8 m/s. What is the centripetal force exerted

on the rope? Round to the tenths place.
Physics
2 answers:
Ksju [112]3 years ago
8 0
You need to round and the answer is 10.8N
Vadim26 [7]3 years ago
5 0

For this case the centripetal force is given by:

F = m * (\frac{v^2}{r})

Where,

m: mass of the object

v: tangential speed

r: rope radius

Substituting values in the equation we have:

F = (4.0) * (\frac{1.8^2}{1.2})

Then, doing the corresponding calculations:

F = 10.8 N

Answer:

The centripetal force exerted on the rope is:

F = 10.8 N

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6 0
3 years ago
The 2.50 kg cube in the figure has edge lengths d = 6.50 cm and is mounted on an axle
kozerog [31]

Answer:

0.191 s

Explanation:

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When the cube is rotated an angle θ, the spring is stretched a distance of r sin θ.  The new vertical distance from the center to the corner is r cos θ.

Sum of the torques:

∑τ = Iα

Fr cos θ = Iα

(k r sin θ) r cos θ = Iα

kr² sin θ cos θ = Iα

k (d²/2) sin θ cos θ = Iα

For a cube rotating about its center, I = ⅙ md².

k (d²/2) sin θ cos θ = ⅙ md² α

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3/2 k sin(2θ) = mα

For small values of θ, sin θ ≈ θ.

3/2 k (2θ) = mα

α = (3k/m) θ

d²θ/dt² = (3k/m) θ

For this differential equation, the coefficient is the square of the angular frequency, ω².

ω² = 3k/m

ω = √(3k/m)

The period is:

T = 2π / ω

T = 2π √(m/(3k))

Given m = 2.50 kg and k = 900 N/m:

T = 2π √(2.50 kg / (3 × 900 N/m))

T = 0.191 s

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A cupboard is placed in front of a heater. Air can move through a gap under the cupboard.
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B

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Answer:

fixed cost $231220

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for 22940 ski masks, total cost =  (22940*13) =  298220

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fixed cost is = 298220 - 67000 = $231220

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