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Rama09 [41]
3 years ago
9

Theresa is swinging a 4.0 kg ball on a 1.2 m long rope with a tangential speed of 1.8 m/s. What is the centripetal force exerted

on the rope? Round to the tenths place.
Physics
2 answers:
Ksju [112]3 years ago
8 0
You need to round and the answer is 10.8N
Vadim26 [7]3 years ago
5 0

For this case the centripetal force is given by:

F = m * (\frac{v^2}{r})

Where,

m: mass of the object

v: tangential speed

r: rope radius

Substituting values in the equation we have:

F = (4.0) * (\frac{1.8^2}{1.2})

Then, doing the corresponding calculations:

F = 10.8 N

Answer:

The centripetal force exerted on the rope is:

F = 10.8 N

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A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this p
olya-2409 [2.1K]

Answer:

Acceleration of proton will be a=0.67\times 10^{11}m/sec^2

Explanation:

We have given a proton is placed in an electric field of intensity of 700 N/C

So electric field E = 700 N/C

Mass of proton m=1.67\times 10^{-27}kg

Charge on proton e=1.6\times 10^{-19}C

So electric force on the proton F=qE=1.6\times 10^{-19}\times 700=1.120\times 10^{-16}N

This force will be equal to force due to acceleration of the proton

According to newton's law force is given by F = ma

So 1.67\times 10^{-27}\times a=1.120\times 10^{-16}

a=0.67\times 10^{11}m/sec^2

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3 years ago
What are the two opposing forces that keep stars between collapsing and inflating?
boyakko [2]
The answer is pressure and gravity
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2 years ago
What is the magnetic field strength required to make a proton with a speed of 5.0 x 10^(5) m/s follow a circular path of radius
Nuetrik [128]

Answer:

Magnetic field strength required for this is 0.25 T

Explanation:

As we know that the proton moves in circular path in uniform magnetic field

so the radius of the path of the circle is given as

R = \frac{mv}{qB}

here we know that

q = 1.6 \times 10^{-19}C

m = 1.6 \times 10^{-27} kg

R = 0.0200 m

v = 5 \times 10^5 m/s

now we have

B = \frac{1.6 \times 10^{-27} (5 \times 10^5)}{(1.6 \times 10^{-19})(0.02)}

so we have

B = 0.25 T

8 0
4 years ago
A mass attached to a vertical spring causes the spring to stretch and the mass to move downwards. What can you say about the pot
poizon [28]

Complete Question

A mass attached to a vertical spring causes the spring to stretch and the mass to move downwards. What can you say about the spring's potential energy Us and the gravitational potential energy Ug of the mass?

A. both Us and Ug decrease

B. Us increases and Ug decreases

C Both Us and Ug increase

D Us decreases and Ug increases

E Us increases and Ug is constant

Answer:

Option B is the correct Answer

Explanation:

    The Gravitational Potential energy is mathematically represented as  

                    U_g = mgh

Where m is the mass , g is the acceleration due to gravity while and h is the height

 And in term of the spring  this energy represents the workdone against gravitational Force

 The Spring potential energy is mathematically represented as

                     U_s = \frac{1}{2} k x^2

Where k is the spring constant ans  x is the extension in the spring

   And energy represents the work that is being done to stretch the spring

 If the system as state in the question is setup and U_s is being increased then U_g decreases

   

8 0
3 years ago
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Describe how mercury in glass thermometer can be constructed?
r-ruslan [8.4K]

Answer:

It consists of a bulb containing mercury attached to a glass tube of narrow diameter; the volume of mercury in the tube is much less than the volume in the bulb. ... The space above the mercury may be filled with nitrogen gas or it may be at less than atmospheric pressure, a partial vacuum.

Explanation:

4 0
2 years ago
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