Answer:
a) KE = 0.0857Joules
b) height = 0.073m
Explanation:
The rotational inertia of the rod at an axis passing through the fixed end is given by:
I = Icm + my
I= 1/12 mL^2 + m(L/2)
I= 1/12 ×0.12×(0.75)^2 + 0.12× (0.75/2)^2
I = 5.625×10^-3 + 0.01688
I = 0.0225Kg/m^-2
a) KE = 1/2 Iw^2
Where I= rotational inertia
w= angular speed at lowest point
KE = 1/2 × 0.0225 ×(2.76)^2
KE= 0.0857 Joules
b) Ki + Ui = Kf + Uf
Ki = Uf - Ui = 0
mgh = K
0.0857= mgh
h = 0.0857/( 0.120× 9.8)
h = 0.0857/ 1.176
h = 0.073m
Answer:
A) a neutron pushing on another neutron.
Explanation:
Neutrons have no charge, therefore, there is no electric force among them. Protons and electrons on the other hand do have electric charge (electrons negative charge and protons positive charge) that generate electric forces between them that can be repelling forces (if the charges are of the same sign), or attractive forces (if the charges are of opposite signs).
Answer:
E. Some charges in the region are positive, and some are negative.
Explanation:
Electric potential is given as;
where;
W is the work done in moving a charge between two points which have a difference in potential
Q is quantity of charge in the given region
If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.
Therefore, the correct statement in the given options is "E"
E. Some charges in the region are positive, and some are negative.
Answer:
41.2 m.
Explanation:
It takes half the time that is (5.8/2) = 2.9 seconds, for the ball to reach its apex.
Given:
S = 83 m
t = 5.8 s
vf = 0 m/s
a = - g
= - 9.81 m/s^2
Equations of motion:
i. vf = vi + a * t
ii. h = vi * t + 1/2 (a * t²)
Using the i. equation of motion:
0 m/s = vi - (9.8 m/s²) (2.9 sec)
vi = 28.4 m/s.
Using the ii. equation of motion:
h = (28.4 * 2.9 ) - 1/2 (9.8 * (2.9)²)
= 82.4 - 41.2
= 41.2 m.
