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mars1129 [50]
3 years ago
10

Definition of AM and Fm Wave? in your own word

Physics
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

In AM broadcasting, the amplitude of the carrier wave is modulated to encode the original sound. In FM broadcasting, the frequency of the carrier wave is modulated to encode the sound. A radio receiver extracts the original program sound from the modulated radio signal and reproduces the sound in a loudspeaker.

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Which of the following is equivalent to 2.5 meters
blsea [12.9K]
B is the correct answer for sure bro
5 0
3 years ago
Read 2 more answers
What holds the positively charged metal ions together within a metallic bond?
enot [183]

Answer:

The electron cloud

Explanation:

Metallic bonds result from interaction of positively charged metal ions with free valence electrons which now forms an electron cloud around the metal ions. Electrostatic interaction between the metal ions and the electron cloud holds the metal ions together in the metallic bond.

4 0
3 years ago
Which sediment size would allow water to flow through at the fastest rate?
xeze [42]
The sediment size that would allow water to flow through at the fastest rate are pebbles. Sediment is a naturally occurring material that is broken down by processes of weathering and erosion, and is consequently transported by the action of wind, or ice, and or by the force of gravity acting on the particles. Pebble is a clast of rock with a particle size of 2 to 64 millimeters based on the scale of sedimentology. 
4 0
3 years ago
Calculate the magnitude of electric field strength at a point 3cm from an infinite line of charge of linear density 18 μC/cm sit
valina [46]
Answer:

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

Explanation:

The linear density:

\begin{gathered} \lambda=18\mu C\text{ /cm} \\  \\ \lambda=\frac{18*10^{-6}C}{0.01m} \\  \\ \lambda=0.0018\text{ C/m} \end{gathered}

Point r = 3 cm = 3/100 m

r = 0.03 m

The electric field strength is calculated below

\begin{gathered} E=\frac{\lambda}{2\pi\epsilon_o\epsilon_rr} \\  \\ E=\frac{0.0018}{2\times3.14\times8.85\times10^{-12}\times1.5\times0.03} \\  \\ E=719709237.468\text{ N/C} \\  \\ E=7.2\times10^8\text{ N/C} \\  \end{gathered}

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

8 0
1 year ago
what would happen to the surface temperature on Earth if large amounts of carbon dioxide were removed from the atmosphere?
slava [35]

Answer:

If carbon emissions stopped, the oceans catch up with the atmosphere, the Earth's temperature would rise about another 1.1F (0.6C).

Explanation:

8 0
3 years ago
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